We can use trigonometry to solve this problem. The height of the plane after traveling 1220 ft can be found by using the tangent function.
Let h be the height of the plane above the field. The tangent of the angle of 11.3 degrees is given by:
\tan(11.3^\circ) = \frac{h}{1220}
Solving for h :
h = 1220 \cdot \tan(11.3^\circ)
h\approx243.4\text{ ft}
Therefore, the height of the plane after it has traveled a distance of 1220 ft is approximately 239.4 ft.
\boxed{243.4\text{ ft}}