A tank has a volume of 3 m3 and contains 65 kg of an ideal gas that has a molecular weight of 55. If the temperature is 35°C, what is the pressure of the gas?

1. Convertimos la temperatura de Celsius a Kelvin:

T = 35 + 273.15 = 308.15 \, K

2. Calculamos el número de moles:

n = \frac{65 \, kg}{55 \, kg/kmol} = \frac{65}{55} \, kmol

3. Usamos la ecuación del gas ideal para encontrar la presión:

P = \frac{nRT}{V}

Sustituimos los valores:

P = \left( \frac{65}{55} \right) \frac{0.08314 \cdot 308.15}{3} \, \text{atm}

4. Realizamos el cálculo:

P\approx1009.258kPa

[Step-by-Step] The answer is:

P\approx1009.258kPa