Question
Applying the definition of module and simplifications, fill in the gaps. |π₯| β 2|π₯ β 3| = { π₯ β 6, π π π₯ < 0 ___________, π π 0 β€ π₯ < ______ ______, π π_________________
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Answer to a math question Applying the definition of module and simplifications, fill in the gaps. |π₯| β 2|π₯ β 3| = { π₯ β 6, π π π₯ < 0 ___________, π π 0 β€ π₯ < ______ ______, π π_________________
Rasheed
4.7103 Answers
1. For \(x < 0\):
2. For \(0 \leq x < 3\):
3. For \(x \geq 3\):
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