Question

At 5:15 p.m. on May 1, 2022, the population of Mexico was 132,373,195. There is one birth in Mexico every 0,29 minutes. Write a lincar function to model the population of Mexico as a function of the number of minutes that has passed since 5:15 p.m. on May 1, 2022. O f(x) =132,373, 195x + 30/100 O f(x) =132, 373, 195x + 100/29 O f(x) = 29/100 +132,373,195 O f(x) = 100/29x + 132,373, 195

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Answer to a math question At 5:15 p.m. on May 1, 2022, the population of Mexico was 132,373,195. There is one birth in Mexico every 0,29 minutes. Write a lincar function to model the population of Mexico as a function of the number of minutes that has passed since 5:15 p.m. on May 1, 2022. O f(x) =132,373, 195x + 30/100 O f(x) =132, 373, 195x + 100/29 O f(x) = 29/100 +132,373,195 O f(x) = 100/29x + 132,373, 195

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Hank
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103 Answers
1. Identify the initial population at 5:15 p.m. on May 1, 2022:
132,373,195

2. Determine the rate of change in population:
One birth every 0.29 minutes means:
\text{Rate} = \frac{1 \text{ birth}}{0.29 \text{ minutes}} = \frac{1}{0.29} = \frac{100}{29} \text{ births per minute}

3. Form the linear function:
f(x) = \text{Rate} \cdot x + \text{Initial Population}
f(x) = \frac{100}{29}x + 132,373,195

4. Provide the final linear function:
f(x) = \frac{100}{29}x + 132,373,195

So, the answer is:
f(x) = \frac{100}{29}x + 132,373,195

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