Solution:
1. The formula for the vertex (h, k) of a parabola y = ax^2 + bx + c is h = -\frac{b}{2a} and k = f(h).
2. Given the equation: y = -x^2 + 4x + 3, where:
- a = -1
- b = 4
- c = 3
3. Calculate the x-coordinate of the vertex:
- h = -\frac{4}{2(-1)} = 2
4. Calculate the y-coordinate of the vertex by substituting h = 2 back into the equation:
- y = -(2)^2 + 4(2) + 3
- y = -4 + 8 + 3
- y = 7
5. The vertex of the parabola is (2, 7).