^x+1 +1 describe transformation","","Solution:\u003Cbr />\n1. Given function:\u003Cbr />\n * \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>y = -24^{x+1} + 1\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Base function:\u003Cbr />\n * \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>y = 4^x\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Identify transformations step-by-step:\u003Cbr />\n - **Translation horizontally**: The function has \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x+1\u003C/math-field>\u003C/math-field> as the exponent instead of \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field>. This indicates a horizontal shift to the left by 1 unit.\u003Cbr />\n - **Vertical stretch and reflection**: The coefficient before \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>4\u003C/math-field>\u003C/math-field> is \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>-2\u003C/math-field>\u003C/math-field>.\u003Cbr />\n - **Vertical stretch**: The factor \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>2\u003C/math-field>\u003C/math-field> indicates that the function is stretched vertically by a factor of \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>2\u003C/math-field>\u003C/math-field>.\u003Cbr />\n - **Reflection**: The negative sign indicates a reflection across the x-axis.\u003Cbr />\n - **Vertical translation**: The \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>+1\u003C/math-field>\u003C/math-field> outside the function indicates a vertical shift upwards by 1 unit.\u003Cbr />\n\u003Cbr />\n4. Describe the complete transformation:\u003Cbr />\n - The function \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>y = 4^x\u003C/math-field>\u003C/math-field> undergoes the following transformations: a horizontal shift to the left by 1 unit, a vertical stretch by a factor of 2, reflection across the x-axis, and finally a vertical shift upwards by 1 unit.",null,1255,251,"y-2-4-x-1-1-describe-transformation",{"id":16,"category":7,"text_question":17,"photo_question":9,"text_answer":18,"step_text_answer":11,"step_photo_answer":11,"views":19,"likes":20,"slug":21},538086,"Add the polynomials gx=x3-2x2+3x-1+4x2-x+2","Solution: \u003Cbr />\n1. Write down the given polynomials:\u003Cbr />\n- First polynomial: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>gx = x^3 - 2x^2 + 3x - 1\u003C/math-field>\u003C/math-field>\u003Cbr />\n- Second polynomial: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>4x^2 - x + 2\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Align and add the polynomials term by term:\u003Cbr />\n- \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>gx = x^3 - 2x^2 + 3x - 1\u003C/math-field>\u003C/math-field>\u003Cbr />\n- \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>4x^2 - x + 2\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Add the corresponding like terms:\u003Cbr />\n- For \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x^3\u003C/math-field>\u003C/math-field> terms: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x^3\u003C/math-field>\u003C/math-field>\u003Cbr />\n- For \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x^2\u003C/math-field>\u003C/math-field> terms: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>-2x^2 + 4x^2 = 2x^2\u003C/math-field>\u003C/math-field>\u003Cbr />\n- For \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field> terms: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>3x - x = 2x\u003C/math-field>\u003C/math-field>\u003Cbr />\n- For constant terms: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>-1 + 2 = 1\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. The resulting polynomial after addition is:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x^3 + 2x^2 + 2x + 1\u003C/math-field>\u003C/math-field>",739,148,"add-the-polynomials-g-x-x3-2x2-3x-1-4x2-x-2",{"id":23,"category":7,"text_question":24,"photo_question":9,"text_answer":25,"step_text_answer":11,"step_photo_answer":11,"views":26,"likes":27,"slug":28},538085,"R=3m. Calculate the volume of the sphere. Round to the nearest tenth if necessary","1. The formula for the volume of a sphere is \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi R^3 \u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>2. Substitute the given radius \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> R = 3 \\, \\text{m} \u003C/math-field>\u003C/math-field> into the formula:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi 3^3 \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>3. Calculate \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> 3^3 = 27 \u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>4. Thus, the volume becomes:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi \\times 27 \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>5. Simplify the expression:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4 \\times 27}{3} \\pi = 36 \\pi \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>6. Use the approximation \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\pi \\approx 3.1416 \u003C/math-field>\u003C/math-field> :\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V \\approx 36 \\times 3.1416 \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>7. Calculate the approximate volume:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V\\approx113.0973\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>8. Round to the nearest tenth:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V \\approx 113.1 \\, \\text{m}^3 \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>Therefore, the volume of the sphere is approximately \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> 113.1 \\, \\text{m}^3 \u003C/math-field>\u003C/math-field> .",1203,241,"r-3m-calculate-the-volume-of-the-sphere-round-to-the-nearest-tenth-if-necessary",{"id":30,"category":7,"text_question":31,"photo_question":9,"text_answer":32,"step_text_answer":11,"step_photo_answer":11,"views":33,"likes":34,"slug":35},538084,"Width of 12 in. Calculate the volume of the sphere. Round to the nearest tenth if necessary","1. Identify the radius of the sphere. Given the width is 12 inches, the diameter is 12 inches. Therefore, the radius is half of the diameter:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> r = \\frac{12}{2} = 6 \\, \\text{in} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Use the formula for the volume of a sphere:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi r^3 \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Substitute the radius into the formula:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi 6^3 \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. Calculate:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi \\times 216 = \\frac{864}{3} \\pi = 288 \\pi \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n5. Approximate using \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\pi \\approx 3.1416 \u003C/math-field>\u003C/math-field>:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V \\approx 288 \\times 3.1416 = 904.8 \\, \\text{in}^3 \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n6. The volume of the sphere, rounded to the nearest tenth, is approximately:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> 904.8 \\, \\text{in}^3 \u003C/math-field>\u003C/math-field>",278,56,"width-of-12-in-calculate-the-volume-of-the-sphere-round-to-the-nearest-tenth-if-necessary",{"id":37,"category":7,"text_question":38,"photo_question":9,"text_answer":39,"step_text_answer":11,"step_photo_answer":11,"views":40,"likes":41,"slug":42},538083,"Calculate the volume tothenearesttenthofacubiccentimeter of a golf ball whose diameter is 4.267cm","1. The formula for the volume of a sphere is given by \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V = \\frac{4}{3} \\pi r^3\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>2. The diameter of the golf ball is given as 4.267 cm, so the radius is half of that: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>r = \\frac{4.267}{2} = 2.1335 \\, \\text{cm}\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>3. Substitute the radius into the volume formula: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V = \\frac{4}{3} \\pi 2.1335^3\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>4. Calculate the cube of the radius: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>2.1335^3 = 9.707432537375\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>5. Substitute this back into the formula: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V=\\frac{4}{3}\\pi\\times9.707432537375\\approx40.7\\,\\text{cm}^3\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>6. The volume of the golf ball is approximately \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>40.7\\,\\text{cm}^3\u003C/math-field>\u003C/math-field> .",1440,288,"calculate-the-volume-to-the-nearest-tenth-of-a-cubic-centimeter-of-a-golf-ball-whose-diameter-is-4-267cm",{"id":44,"category":7,"text_question":45,"photo_question":9,"text_answer":46,"step_text_answer":11,"step_photo_answer":11,"views":47,"likes":48,"slug":49},538082,"Find the length of each base edge tothenearesttenthofameter of the 24m tall glass square pyramids of the Muttart Conservatory in Alberta, Canada, if each contains 5280m^3 of space","1. Volume V of a square pyramid is given by the formula:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V = \\frac{1}{3} B h\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>where B is the area of the base and h is the height of the pyramid.\u003Cbr>\u003Cbr>2. Given that the height h = 24 m and the volume V = 5280 m^3.\u003Cbr>\u003Cbr>3. The base is square, so if the side length of the base is s, then:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>B = s^2\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>4. Substituting into the volume formula:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>5280 = \\frac{1}{3} s^2 \\times 24\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>5. Simplify and solve for s^2:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>5280 = 8 s^2\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>s^2 = \\frac{5280}{8} = 660\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>6. Solve for s:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>s = \\sqrt{660} \\approx 25.7\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>7. To find the length of each base edge to the nearest tenth of a meter, compute:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>s \\approx 25.7 \\, \\text{m}\u003C/math-field>\u003C/math-field>",418,84,"find-the-length-of-each-base-edge-to-the-nearest-tenth-of-a-meter-of-the-24m-tall-glass-square-pyramids-of-the-muttart-conservatory-in-alberta-canada-if-each-contains-5280m-3-of-space",{"id":51,"category":7,"text_question":52,"photo_question":9,"text_answer":53,"step_text_answer":11,"step_photo_answer":11,"views":54,"likes":55,"slug":56},538081,"An observer is 150 meters away\n distance of a hot air balloon online\n straight line at ground level. From your position,\n measures an elevation angle of 40Β° up to\n the base of the balloon. At what height is\n find the hot air balloon?","Solution:\u003Cbr />\n1. Dado:\u003Cbr />\n- Distancia horizontal desde el observador hasta la base del globo: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>d = 150 \\ m\u003C/math-field>\u003C/math-field>\u003Cbr />\n- Ángulo de elevaciΓ³n: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>\\theta = 40^{\\circ}\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Usamos la funciΓ³n tangente para encontrar la altura \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>h\u003C/math-field>\u003C/math-field> del globo aerostΓ‘tico. La tangente de un Γ‘ngulo en un triΓ‘ngulo rectΓ‘ngulo es la razΓ³n entre la altura y la distancia horizontal:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>\\tantheta = \\frac{h}{d}\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Sustituimos los valores conocidos en la ecuaciΓ³n:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>\\tan40circ = \\frac{h}{150}\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. Resolvemos para \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>h\u003C/math-field>\u003C/math-field>:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>h = 150 \\times \\tan40circ\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n5. Calculamos el valor numΓ©rico:\u003Cbr />\n* Usando una calculadora, \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>\\tan40circ \\approx 0.8391\u003C/math-field>\u003C/math-field>\u003Cbr />\n* Entonces: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>h \\approx 150 \\times 0.8391 = 125.865 \\ m\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\nLa altura del globo aerostΓ‘tico es aproximadamente \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>125.865 \\ m\u003C/math-field>\u003C/math-field>.",667,133,"an-observer-is-150-meters-away-distance-of-a-hot-air-balloon-online-straight-line-at-ground-level-from-your-position-measures-an-elevation-angle-of-40-up-to-the-base-of-the-balloon-at-what-hei",{"id":58,"category":7,"text_question":59,"photo_question":9,"text_answer":60,"step_text_answer":11,"step_photo_answer":11,"views":61,"likes":62,"slug":63},538080,"A plane ticket has gone up 18%, now costing 4,720.Howmuchdiditcostbeforetheincrease?","\u003Cmathβˆ’fieldreadβˆ’onlydefaultβˆ’mode=\"inlineβˆ’math\"class=\"mathβˆ’expression\">\u003Cmathβˆ’fieldreadβˆ’only>textSolution:\u003C/mathβˆ’field>\u003C/mathβˆ’field>\u003Cbr/>\n1.Definevariables:\u003Cbr/>\nβˆ’Let\u003Cmathβˆ’fieldreadβˆ’onlydefaultβˆ’mode=\"inlineβˆ’math\"class=\"mathβˆ’expression\">\u003Cmathβˆ’fieldreadβˆ’only>P\u003C/mathβˆ’field>\u003C/mathβˆ’field>betheoriginalpriceoftheplaneticket.\u003Cbr/>\nβˆ’\u003Cmathβˆ’fieldreadβˆ’onlydefaultβˆ’mode=\"inlineβˆ’math\"class=\"mathβˆ’expression\">\u003Cmathβˆ’fieldreadβˆ’only>P\u003C/mathβˆ’field>\u003C/mathβˆ’field>increasedby18\\frac{x}{15}=\\frac{4}{3}\u003C/mathβˆ’field>\n\u003Cbr>\n\u003C/div>\n\n\u003Cdiv>\n\n\u003Cmathβˆ’fieldstyle=\"fontβˆ’size:16px;padding:8px;borderβˆ’radius:8px;border:1pxsolidrgba(0,0,0,.3);boxβˆ’shadow:000rgba(0,0,0,.2)\n\"readβˆ’only>x=20\u003C/math-field>\n    \u003Cbr>\n  \u003C/div>",467,93,"15-75-of",{"id":121,"category":7,"text_question":122,"photo_question":9,"text_answer":123,"step_text_answer":11,"step_photo_answer":11,"views":124,"likes":62,"slug":125},538067,"Naria Wants to build a perimeter wall fence around 400 sqm lot. The frontage of the lot is 20 meters. The wall height is 1.2 meters below the ground and 3.8 meters above the ground .\nThe cost of constructing the wall is 750 per square meter. Additionally,she plans to install a 5-meter-wide gate that costs β‚±50,000.\nHow much Maria spend in total for the wall and the gate\na. Php 281,250.00\nb. Php 106,250.00\nc. Php 331,250.00\nd. Php 218,250.00","1. Determine the dimensions of the lot. Given the frontage is 20 meters, calculate the other side using the area:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Area} = 20 \\times x = 400 \u003C/math-field>\u003C/math-field>\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> x = \\frac{400}{20} = 20 \\, \\text{meters} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Calculate the perimeter of the lot:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Perimeter} = 2 \\times (20 + 20) = 80 \\, \\text{meters} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Calculate the total height of the wall:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Total height} = 1.2 + 3.8 = 5 \\, \\text{meters} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. Calculate the wall area excluding the gate:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Wall area} = (\\text{Perimeter} - \\text{Gate width}) \\times \\text{Total height} \u003C/math-field>\u003C/math-field>\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Wall area} = (80 - 5) \\times 5 = 75 \\times 5 = 375 \\, \\text{sqm} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n5. Calculate the cost of the wall:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Wall cost} = 375 \\times 750 = 281,250 \\, \\text{PHP} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n6. Calculate total cost including the gate:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Total cost} = \\text{Wall cost} + \\text{Gate cost} \u003C/math-field>\u003C/math-field>\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Total cost} = 281,250 + 50,000 = 331,250 \\, \\text{PHP} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n7. Therefore, the total cost is: \u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Php} \\, 331,250.00 \u003C/math-field>\u003C/math-field>",727,"naria-wants-to-build-a-perimeter-wall-fence-around-400-sqm-lot-the-frontage-of-the-lot-is-20-meters-the-wall-height-is-1-2-meters-below-the-ground-and-3-8-meters-above-the-ground-the-cost-of-const",{"id":127,"category":7,"text_question":128,"photo_question":9,"text_answer":129,"step_text_answer":11,"step_photo_answer":11,"views":130,"likes":48,"slug":131},538066,"2. A rectangular lot has a\n30 meters.\nallocated along the frontage. What is the gross area\nfrontage of 18 meters and a depth of\nHowever, a public right of way of 3 meters is\nReve\nof\nthe\nlot?\na. 520 sqm\nb. 540 sqm\nC. 560 sqm\nd. 580 sqm\nReV","1. Calculate the area of the rectangular lot without the right of way:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Area}_{\\text{total}} = \\text{frontage} \\times \\text{depth} = 18 \\, \\text{m} \\times 30 \\, \\text{m} = 540 \\, \\text{sqm} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. No need to subtract any area because the problem states that the right of way has already been accounted for in the dimensions provided.\u003Cbr />\n\u003Cbr />\n3. Therefore, the gross area of the lot remains:\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> 540 \\, \\text{sqm} \u003C/math-field>\u003C/math-field> \u003Cbr />\n   \u003Cbr />\nThus, the answer is \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>540 \\, \\text{sqm}\u003C/math-field>\u003C/math-field>.",420,"2-a-rectangular-lot-has-a-30-meters-allocated-along-the-frontage-what-is-the-gross-area-frontage-of-18-meters-and-a-depth-of-however-a-public-right-of-way-of-3-meters-is-reve-of-the-lot-a-520-sq",{"id":133,"category":7,"text_question":134,"photo_question":9,"text_answer":135,"step_text_answer":11,"step_photo_answer":11,"views":136,"likes":137,"slug":138},538065,"A triangular lot has a base of 15 meters and heights of 10 meters . What is the total area of the lot ?","1. The formula for the area of a triangle is given by:\u003Cbr />\n\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> A = \\frac{1}{2} \\times \\text{base} \\times \\text{height} \u003C/math-field>\u003C/math-field> \u003Cbr />\n\u003Cbr />\n2. Substitute the given values into the formula:\u003Cbr />\n\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> A = \\frac{1}{2} \\times 15 \\times 10 \u003C/math-field>\u003C/math-field> \u003Cbr />\n\u003Cbr />\n3. Calculate the area:\u003Cbr />\n\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> A = \\frac{1}{2} \\times 150 \u003C/math-field>\u003C/math-field> \u003Cbr />\n\u003Cbr />\n4. Simplify the expression:\u003Cbr />\n\u003Cbr />\n   \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> A = 75 \u003C/math-field>\u003C/math-field> \u003Cbr />\n\u003Cbr />\nTherefore, the total area of the lot is \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>75 \\, \\text{square meters}\u003C/math-field>\u003C/math-field>.",425,85,"a-triangular-lot-has-a-base-of-15-meters-and-heights-of-10-meters-what-is-the-total-area-of-the-lot",{"id":140,"category":7,"text_question":141,"photo_question":9,"text_answer":142,"step_text_answer":11,"step_photo_answer":11,"views":143,"likes":144,"slug":145},538064,"4x+(x-3)=2x-(3x-4)+5","Solution:\u003Cbr />\n1. Simplify both sides of the equation.\u003Cbr />\n- Left side: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>4x + (x - 3) = 4x + x - 3 = 5x - 3\u003C/math-field>\u003C/math-field>\u003Cbr />\n- Right side: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>2x - (3x - 4) + 5 = 2x - 3x + 4 + 5 = -x + 9\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. The equation is now: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>5x - 3 = -x + 9\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Add \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field> to both sides to eliminate the \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>-x\u003C/math-field>\u003C/math-field> from the right side and simplify:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>5x + x - 3 = 9\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. Simplify: \u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>6x - 3 = 9\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n5. Add 3 to both sides to isolate terms with \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field>:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>6x = 9 + 3\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n6. Simplify:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>6x = 12\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n7. Divide both sides by 6 to solve for \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field>:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x = \\frac{12}{6}\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n8. Simplify the fraction:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x = 2\u003C/math-field>\u003C/math-field>",1332,266,"4x-x-3-2x-3x-4-5",{"first":147,"last":148,"prev":11,"next":149},1,187,2,{"current_page":147,"from":147,"last_page":148,"links":151,"path":189,"per_page":190,"to":190,"total":191},[152,155,158,161,164,167,170,173,176,179,182,185,187],{"url":147,"label":153,"active":154},"1",true,{"url":149,"label":156,"active":157},"2",false,{"url":159,"label":160,"active":157},3,"3",{"url":162,"label":163,"active":157},4,"4",{"url":165,"label":166,"active":157},5,"5",{"url":168,"label":169,"active":157},6,"6",{"url":171,"label":172,"active":157},7,"7",{"url":174,"label":175,"active":157},8,"8",{"url":177,"label":178,"active":157},9,"9",{"url":180,"label":181,"active":157},10,"10",{"url":183,"label":184,"active":157},186,"186",{"url":148,"label":186,"active":157},"187",{"url":149,"label":188,"active":157},"Next »","https://api.math-master.org/api/question",20,3737,{"data":193},[194,196,198,200,202,204],{"id":147,"title":195,"slug":11},"Algebra",{"id":149,"title":197,"slug":11},"Geometry",{"id":159,"title":199,"slug":11},"Coordinate-geometry",{"id":162,"title":201,"slug":11},"Statistics",{"id":165,"title":203,"slug":11},"Calculus",{"id":168,"title":205,"slug":11},"General",{"data":207},[208,209,210,211,212,213],{"id":147,"title":195,"slug":11},{"id":149,"title":197,"slug":11},{"id":159,"title":199,"slug":11},{"id":162,"title":201,"slug":11},{"id":165,"title":203,"slug":11},{"id":168,"title":205,"slug":11},{"data":215},{"id":216,"category":7,"slug":217,"text_question":218,"photo_question":11,"text_answer":219,"step_text_answer":11,"step_photo_answer":11,"views":220,"likes":221,"expert":222},534440,"to-find-the-increased-amount-on-a-standard-term-deposit-with-the-following-conditions-starting-amount-bgn-13000-type-of-deposit-annual-annual-compound-interest-rate-1-4-after-4-years","To find the increased amount on a standard term deposit with the following conditions:\n\nstarting amount: BGN 13000,\ntype of deposit: annual,\nannual compound interest rate: 1.4%,\nafter 4 years;","First, convert R as a percent to r as a decimal\nr = R/100\nr = 1.4/100\nr = 0.014 rate per year,\n\nThen solve the equation for A\n\u003Cmath-field read-only> A=P\\left(1+\\frac{r}{n}\\right)^{}^{nt} \u003C/math-field>\n\u003Cmath-field read-only> A=13,000.00\\left(1+\\frac{0.014}{1}\\right)^{}^{1*4} \u003C/math-field>\n\u003Cmath-field read-only> A=13,000.00\\left(1+0.014\\right)^{}^{4} \u003C/math-field>\n\u003Cmath-field read-only> A=13,000.00\\left(1.014\\right)^{}^{4} \u003C/math-field>\n\u003Cmath-field read-only> A= BGN 13,743.43 \u003C/math-field>\nAnswer:\nA = BGN 13,743.43",752,150,{"id":223,"name":224,"photo":225,"biography":226,"created_at":11,"updated_at":11,"rating":227,"total_answer":97},29,"Eliseo","https://api.math-master.org/img/experts/29/29.webp","In my school days I was not good in Mathematics but there was something which always attracted me towards Mathematics as playing with numbers and doing round of questions of different exercises of workbook was fun for me and as a hobby I inclined to Math's. I never thought of teaching mathematics and making a career out of it but somethings bound to happen.",4.6,{"data":229},{"questions":230},[231,235,239,242,246,250,254,258,262,266,270,274,278,282,286,290,294,298,302,306],{"id":232,"category":7,"text_question":233,"slug":234},532009,"How much volume of water in MegaLiters (ML) is required to irrigate 30 Hectare crop\narea with depth of 20mm?","how-much-volume-of-water-in-megaliters-ml-is-required-to-irrigate-30-hectare-crop-area-with-depth-of-20mm",{"id":236,"category":7,"text_question":237,"slug":238},532307,"Write 32/25 as a percent","write-32-25-as-a-percent",{"id":240,"category":7,"text_question":241,"slug":241},533938,"132133333-33",{"id":243,"category":7,"text_question":244,"slug":245},533979,"A bird randomly chooses to land on 1 of 12 perches available in its aviary. Determine the Probability of it landing on a perch numbered 8 and then on a perch marked with a prime number; take into account that he never lands on the same perch in the sequence.","a-bird-randomly-chooses-to-land-on-1-of-12-perches-available-in-its-aviary-determine-the-probability-of-it-landing-on-a-perch-numbered-8-and-then-on-a-perch-marked-with-a-prime-number-take-into-acco",{"id":247,"category":7,"text_question":248,"slug":249},534015,"(5u + 6)-(3u+2)=","5u-6-3u-2",{"id":251,"category":7,"text_question":252,"slug":253},534043,"The equation of the circle that passes through (5,3) and is tangent to the abscissa axis at x=2 is\n a.(x-2)^2 (y 3)^2 = 9\n b.(x-2)^2 (y-3)^2 = 9\n c.(x-2)^2 (y-3)^2 = 4\n d.(x-2)^2 (y 1)^2 = 4\n e.(x-2)^2 (y-1)^2 = 4","the-equation-of-the-circle-that-passes-through-5-3-and-is-tangent-to-the-abscissa-axis-at-x-2-is-a-x-2-2-y-3-2-9-b-x-2-2-y-3-2-9-c-x-2-2-y-3-2-4-d-x-2-2-y-1-2-4-e-x-2",{"id":255,"category":7,"text_question":256,"slug":257},534078,"is the x element (180,270), if tanx-3cotx=2, sinx ?","is-the-x-element-180-270-if-tanx-3cotx-2-sinx",{"id":259,"category":7,"text_question":260,"slug":261},534134,"find x in the equation\n 2x-4=6","find-x-in-the-equation-2x-4-6",{"id":263,"category":7,"text_question":264,"slug":265},534235,"Equine infectious anemia (EIA) is considered the main infectious disease in Brazilian equine farming, for which there is no effective vaccine or treatment. It is caused by a retrovirus of the genus Lentivirus, which affects horses, donkeys and mules and is transmitted in nature mainly by hematophagous insects of the genus Tabanidae.\n\n Researchers analyzed the records of 9,439 equids from Acre, submitted to the agar gel immunodiffusion test (AGID) for equine infectious anemia (EIA), between 1986 and 1996. Of these, 6199 tested positive for equine infectious anemia (EIA) .\n\n Knowing that the age of AIE-positive horses follows a Normal distribution with a mean of 5 years and a standard deviation of 1.5 years, determine the expected number of AIE-positive horses in the Acre sample that will be aged less than or equal to 3 years.\n\n\n\n ATTENTION: Provide the answer to exactly FOUR decimal places.","equine-infectious-anemia-eia-is-considered-the-main-infectious-disease-in-brazilian-equine-farming-for-which-there-is-no-effective-vaccine-or-treatment-it-is-caused-by-a-retrovirus-of-the-genus-le",{"id":267,"category":7,"text_question":268,"slug":269},534277,"In an audience of 4000 people, 2 people are chosen, at random, to appear on stage. How many ways can the people be chosen?","in-an-audience-of-4000-people-2-people-are-chosen-at-random-to-appear-on-stage-how-many-ways-can-the-people-be-chosen",{"id":271,"category":7,"text_question":272,"slug":273},534309,"Determine the increase of the function y=4xβˆ’5 when the argument changes from x1=2 to x2=3","determine-the-increase-of-the-function-y-4x-5-when-the-argument-changes-from-x1-2-to-x2-3",{"id":275,"category":7,"text_question":276,"slug":277},534394,"In a physics degree course, there is an average dropout of 17 students in the\n first semester. What is the probability that the number of dropouts in the first\n semester in a randomly selected year has between 13 and 16 students?","in-a-physics-degree-course-there-is-an-average-dropout-of-17-students-in-the-first-semester-what-is-the-probability-that-the-number-of-dropouts-in-the-first-semester-in-a-randomly-selected-year-ha",{"id":279,"category":7,"text_question":280,"slug":281},534408,"Which statement best describes the key changes in perspectives on inclusion?\r\n\r\n\t\t\r\nAn inclusive program must consider the unique experiences of every child and family as well as the child's strengths and needs.\r\n\r\n\t\t\r\nThere is a shift in thinking about individual programs as \"inclusive programs\" to thinking about inclusion as something that reflects the cultural influence of the family.\r\n\r\n\t\t\r\nThere is a greater emphasis on barriers to full participation and the acknowledgement that all children are unique and must be fully and meaningfully engaged in a program.\r\n\r\n\t\t\r\nIn an inclusive program all participants are accepted by their peers and other members of the community.","which-statement-best-describes-the-key-changes-in-perspectives-on-inclusion-an-inclusive-program-must-consider-the-unique-experiences-of-every-child-and-family-as-well-as-the-child-s-strengths",{"id":283,"category":7,"text_question":284,"slug":285},534432,"Calculate the change in internal energy of a gas that receives 16000 J of heat at constant pressure (1.3 atm) expanding from 0.100 m3 to 0.200 m3.\n\n Question 1Answer\n to.\n 7050J\n\n b.\n 2125J\n\n c.\n None of the above\n\n d.\n 2828J\n\n and.\n 10295 J","calculate-the-change-in-internal-energy-of-a-gas-that-receives-16000-j-of-heat-at-constant-pressure-1-3-atm-expanding-from-0-100-m3-to-0-200-m3-question-1answer-to-7050j-b-2125j-c-none",{"id":287,"category":7,"text_question":288,"slug":289},534437,"nI Exercises 65-68, the latitudes of a pair of cities are given. Assume that one city si directly south of the other and that the earth is a perfect sphere of radius 4000 miles. Use the arc length formula in terms of degrees to find the distance between the two cities.\n65. The North Pole: latitude 90Β° north Springfield, Illinois: latitude 40Β° north","ni-exercises-65-68-the-latitudes-of-a-pair-of-cities-are-given-assume-that-one-city-si-directly-south-of-the-other-and-that-the-earth-is-a-perfect-sphere-of-radius-4000-miles-use-the-arc-length-for",{"id":291,"category":7,"text_question":292,"slug":293},534524,"xΒ²-7x+12=0","x-7x-12-0",{"id":295,"category":7,"text_question":296,"slug":297},534533,"8/9 divided by 10/6","8-9-divided-by-10-6",{"id":299,"category":7,"text_question":300,"slug":301},534546,"The mean of 4 numbers is 5 and the mean of 3 different numbers is 12. What is the mean of the 7 numbers together? Produce an algebraic solution. Guess and check is  acceptable.","the-mean-of-4-numbers-is-5-and-the-mean-of-3-different-numbers-is-12-what-is-the-mean-of-the-7-numbers-together-produce-an-algebraic-solution-guess-and-check-is-acceptable",{"id":303,"category":7,"text_question":304,"slug":305},534638,"Sin(5pi/3)","sin-5pi-3",{"id":307,"category":7,"text_question":308,"slug":309},534664,"15=5(x+3)","15-5-x-3",{"data":311},{"questions":312},[313,317,321,325,329,333,337,341,345,349,353,357,361,365,366,370,374,378,382,386],{"id":314,"category":7,"text_question":315,"slug":316},532025,"given cos26=k find cos13","given-cos26-k-find-cos13",{"id":318,"category":7,"text_question":319,"slug":320},532047,"2+2","2-2",{"id":322,"category":7,"text_question":323,"slug":324},532052,"-6n+5=-13","6n-5-13",{"id":326,"category":7,"text_question":327,"slug":328},532093,"Karina has a plot of 5000 square meters in which she has decided that 60% of it will be used to plant vegetables. Of this part, 12% will be dedicated to planting lettuce. How much surface area of the plot will be used to grow lettuce?","karina-has-a-plot-of-5000-square-meters-in-which-she-has-decided-that-60-of-it-will-be-used-to-plant-vegetables-of-this-part-12-will-be-dedicated-to-planting-lettuce-how-much-surface-area-of-the",{"id":330,"category":7,"text_question":331,"slug":332},532298,"Consider the relation R defined on the set of positive integers as (x,y) βˆˆ R if x divides y. Choose all the true statements.\nR is reflexive.\nR is symmetric.\nR is antisymmetric.\nR is transitive.\nR is a partial order.\nR is a total order.\nR is an equivalence relation.","consider-the-relation-r-defined-on-the-set-of-positive-integers-as-x-y-r-if-x-divides-y-choose-all-the-true-statements-r-is-reflexive-r-is-symmetric-r-is-antisymmetric-r-is-transitive-r-is-a",{"id":334,"category":7,"text_question":335,"slug":336},534038,"What is the r.p.m. required to drill a 13/16\" hole in mild steel if the cutting speed is 100 feet per minute?","what-is-the-r-p-m-required-to-drill-a-13-16-hole-in-mild-steel-if-the-cutting-speed-is-100-feet-per-minute",{"id":338,"category":7,"text_question":339,"slug":340},534096,"A construction company is working on two projects: house construction and building construction. Each house requires 4 weeks of work and produces a profit of50,000. Each building requires 8 weeks of work and produces a profit of 100,000.Thecompanyhasatotalof24workweeksavailable.\nFurthermore,itisknownthatatleast2housesandatleast1buildingmustbebuilttomeetthedemand.Thecompanywantstomaximizeitsprofitsandneedstodeterminehowmanyhousesandbuildingsitshouldbuildtomeetdemandandmaximizeprofits,giventimeanddemandconstraints.","aβˆ’constructionβˆ’companyβˆ’isβˆ’workingβˆ’onβˆ’twoβˆ’projectsβˆ’houseβˆ’constructionβˆ’andβˆ’buildingβˆ’constructionβˆ’eachβˆ’houseβˆ’requiresβˆ’4βˆ’weeksβˆ’ofβˆ’workβˆ’andβˆ’producesβˆ’aβˆ’profitβˆ’ofβˆ’50βˆ’000βˆ’eachβˆ’buildingβˆ’requiresβˆ’8βˆ’weeksβˆ’of","id":342,"category":7,"textquestion":343,"slug":344,534106,"Findtheequationofthelineperpendiculartoβˆ’5π‘₯βˆ’3𝑦+5=0passingthroughthepoint(0,βˆ’2)","findβˆ’theβˆ’equationβˆ’ofβˆ’theβˆ’lineβˆ’perpendicularβˆ’toβˆ’5xβˆ’3yβˆ’5βˆ’0βˆ’passingβˆ’throughβˆ’theβˆ’pointβˆ’0βˆ’2","id":346,"category":7,"textquestion":347,"slug":348,534122,"ThedurabilityofatireofacertainbrandisaNormalrandomvariablewithanaverageof64,000kmandastandarddeviationof9,000km.Assumingindependencebetweentires,whatistheprobabilitythatthe4tiresonacarwilllastmorethan58,000km?","theβˆ’durabilityβˆ’ofβˆ’aβˆ’tireβˆ’ofβˆ’aβˆ’certainβˆ’brandβˆ’isβˆ’aβˆ’normalβˆ’randomβˆ’variableβˆ’withβˆ’anβˆ’averageβˆ’ofβˆ’64βˆ’000βˆ’kmβˆ’andβˆ’aβˆ’standardβˆ’deviationβˆ’ofβˆ’9βˆ’000βˆ’kmβˆ’assumingβˆ’independenceβˆ’betweenβˆ’tiresβˆ’whatβˆ’isβˆ’theβˆ’probability","id":350,"category":7,"textquestion":351,"slug":352,534230,"User\nBeforetheelection,apollof60votersfoundtheproportionwhosupporttheGreencandidatetobe25sicons":402},{"bxl:facebook-circle":403,"bxl:instagram":407,"mdi:web":409,"la:apple":411,"ph:google-logo-bold":414,"ph:google-logo":417},{"left":404,"top":404,"width":405,"height":405,"rotate":404,"vFlip":157,"hFlip":157,"body":406},0,24,"\u003Cpath 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