Find the length of each base edge (to the nearest tenth of a meter) of the 24m tall glass square pyramids of the Muttart Conservatory in Alberta, Canada, if each contains 5280m^3 of space

1. Volume V of a square pyramid is given by the formula:

V = \frac{1}{3} B h

where B is the area of the base and h is the height of the pyramid.

2. Given that the height h = 24 m and the volume V = 5280 m^3.

3. The base is square, so if the side length of the base is s, then:

B = s^2

4. Substituting into the volume formula:

5280 = \frac{1}{3} s^2 \times 24

5. Simplify and solve for s^2:

5280 = 8 s^2

s^2 = \frac{5280}{8} = 660

6. Solve for s:

s = \sqrt{660} \approx 25.7

7. To find the length of each base edge to the nearest tenth of a meter, compute:

s \approx 25.7 \, \text{m}