For a randomly selected subject, find the probability of a score greater than -2.93

Solution:
1. Given:
- We are working with a standard normal distribution, mean \mu = 0, standard deviation \sigma = 1.
- We want to find the probability that the score Z is greater than -2.93.

2. Use the standard normal distribution table (Z-table) to find the cumulative probability for Z = -2.93.
- Cumulative probability for Z < -2.93 (from Z-table) is approximately 0.0017.

3. To find the probability of Z > -2.93, we subtract the cumulative probability from 1:
P(Z > -2.93) = 1 - P(Z < -2.93)
P(Z > -2.93) = 1 - 0.0017 = 0.9983

4. Therefore, the probability that a randomly selected subject has a score greater than -2.93 is 0.9983.