Question
If eight basketball teams participate in a tournament, find the number of different ways that first, second, and third places can be decided assuming that no ties are allowed.
262
likes1308 views
Answer to a math question If eight basketball teams participate in a tournament, find the number of different ways that first, second, and third places can be decided assuming that no ties are allowed.
Miles
4.9114 Answers
We are given 8 teams (objects) to arrange them in 3 places in different ways. We are asked to calculate the permutations of 8 different things taken 3 at a time. This will be given by :
^8P_3=\frac{8^{}!}{\left(8-3\right)!}=\frac{8!}{5!}
=8\times7\times6
=336
So, we can arrange the 8 teams in 336 different ways to 1st, 2nd and 3rd position.
Frequently asked questions (FAQs)
How many ways can 3 people be selected from a group of 7 for a committee?
+
What is the measure of an angle formed by two intersecting lines, if the alternate interior angle measures 120°?
+
What are the characteristics of a hyperbola function with equation (x^2/36) - (y^2/25) = 1?
+
New questions in Mathematics