Question
If eight basketball teams participate in a tournament, find the number of different ways that first, second, and third places can be decided assuming that no ties are allowed.
262
likes1308 views
Answer to a math question If eight basketball teams participate in a tournament, find the number of different ways that first, second, and third places can be decided assuming that no ties are allowed.
Miles
4.9114 Answers
We are given 8 teams (objects) to arrange them in 3 places in different ways. We are asked to calculate the permutations of 8 different things taken 3 at a time. This will be given by :
^8P_3=\frac{8^{}!}{\left(8-3\right)!}=\frac{8!}{5!}
=8\times7\times6
=336
So, we can arrange the 8 teams in 336 different ways to 1st, 2nd and 3rd position.
Frequently asked questions (FAQs)
What is the product of 5 and the mixed number 2 1/4 when factored together considering real numbers?
+
Math question: What is the integral of x^2 with respect to x using the power rule? (
+
Math question: What is the smallest positive integer solution for Fermat's theorem: a^n + b^n = c^n, where n>2? (
+
New questions in Mathematics