How long did it take for the beam to reach a speed of 22 m/s moving with friction covered a distance of 70 m? 3 m/s2 Bury the drum of the beginning of this movement too!

To find the time it took for the beam to reach a speed of 22 m/s, we can use the equation of motion:

v = u + at

where:
- v is the final velocity (22 m/s),
- u is the initial velocity (0 m/s as the beam starts from rest),
- a is the acceleration (given as 3 m/s^2), and
- t is the time taken.

We can rearrange the equation to solve for t:

t = \frac{{v - u}}{{a}}

Substituting the given values:

t = \frac{{22 \, \text{m/s} - 0 \, \text{m/s}}}{{3 \, \text{m/s}^2}}

Simplifying:

t = \frac{{22 \, \text{m/s}}}{{3 \, \text{m/s}^2}}

Therefore, the time it took for the beam to reach a speed of 22 m/s is:

t = 7.3 \, \text{s}

Answer: \boxed{7.3 \, \text{s}}