Linear function passes through the points (16,8) and (4,2). The intersection point at the Y is _____ and the slope has a value of ______

First, find the slope \(m\) using the formula:
m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 8}{4 - 16} = \frac{-6}{-12} = \frac{1}{2}

Then, use the point-slope form of the linear equation:
y - y_1 = m(x - x_1)

Using one of the points, \((16,8)\):
y - 8 = \frac{1}{2}(x - 16)

Simplify to the slope-intercept form \(y = mx + b\):
y - 8 = \frac{1}{2}x - 8
y = \frac{1}{2}x

Therefore, the intersection point at the Y (Y-intercept) is:
Y = 0

And the slope is:
m = \frac{1}{2}

Answer:
Y = 0
m = \frac{1}{2}