Question
show how to do 14+231 in a base 12 system
236
likes1182 views
Answer to a math question show how to do 14+231 in a base 12 system
Rasheed
4.7110 Answers
Solution:
1. Express the numbers in their base 10 equivalent:
-14_{12} = 1 \cdot 12^1 + 4 \cdot 12^0 = 12 + 4 = 16
-231_{12} = 2 \cdot 12^2 + 3 \cdot 12^1 + 1 \cdot 12^0 = 288 + 36 + 1 = 325
2. Add the numbers in base 10:
-16 + 325 = 341
3. Convert the sum back to base 12:
- To convert 341 to base 12, divide by 12 and keep track of the remainders.
-341 \div 12 = 28 5
-28 \div 12 = 2 4
-2 \div 12 = 0 2
4. Read the remainders from last to first to get245_{12}
Thus,14_{12} + 231_{12} = 245_{12}
1. Express the numbers in their base 10 equivalent:
-
-
2. Add the numbers in base 10:
-
3. Convert the sum back to base 12:
- To convert 341 to base 12, divide by 12 and keep track of the remainders.
-
-
-
4. Read the remainders from last to first to get
Thus,
Frequently asked questions (FAQs)
Question: Find the absolute extrema for the function f(x) = x^2 - 4x + 5 on the closed interval [-2, 4].
+
Math question: Find the factors of 56 using the factoring formula.
+
Math question: Find the square root of 225, simplifying the answer, and express it as a mixed number if possible.
+
New questions in Mathematics