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solve p l s q 2 3 6 10 6 d 5 for p where p backpressure in kilopascals l 264 2615996 meters s 1 135544434 kilograms meter

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solve P = (L * S * Q^2 3.6 10^6)/D^5 for P where P = backpressure in kilopascals L = 264.2615996 meters S = 1.135544434 kilograms/meter^3 Q = 5.663369322 meters^3/minute D = 101.6 millimeters

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Answer to a math question solve P = (L * S * Q^2 3.6 10^6)/D^5 for P where P = backpressure in kilopascals L = 264.2615996 meters S = 1.135544434 kilograms/meter^3 Q = 5.663369322 meters^3/minute D = 101.6 millimeters

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102 Answers

P = \frac{L \cdot S \cdot Q^2 \cdot 3.6 \cdot 10^6}{D^5}

Given:
-

L = 264.2615996

meters
-

S = 1.135544434

kilograms/meter

^3

-

Q = 5.663369322

meters

^3

/minute
-

D = 101.6

millimeters

### Step 1: Convert

D

to meters

D = 101.6 \, \text{mm} \times \frac{1 \, \text{m}}{1000 \, \text{mm}} = 0.1016 \, \text{m}

### Step 2: Calculate

Q^2

Q^2 = (5.663369322)^2 = 32.07375207737074

### Step 3: Substitute values into the formula

P = \frac{264.2615996 \cdot 1.135544434 \cdot (32.07375207737074) \cdot 3.6 \times 10^6}{(0.1016)^5}

### Answer:

P = 3,200,530,139,279,840 \, \text{kPa}

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