Question

Use the sample data and confidence level given below to complete parts (a) through (d). A drug is used to help prevent blood clots in certain patients. In clinical trials, among 4336 patients treated with the drug, 194 developed the adverse reaction of nausea. Construct a 99% confidence interval for the proportion of adverse reactions.

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Madelyn

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82 Answers

Lower bound: \frac{194}{4336}-2.576\sqrt{\frac{194(4336-194)}{4336^3}}=0.0367
Upper bound: \frac{194}{4336}+2.576\sqrt{\frac{194(4336-194)}{4336^3}}=0.0528
0.0367 < p < 0.0528

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