What volume of a 2 M HCl solution is needed to prepare 500 mL of a 0.5 M HCl solution?

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Answer to a math question What volume of a 2 M HCl solution is needed to prepare 500 mL of a 0.5 M HCl solution?

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M_1 = 2 \text{ M}

M_2 = 0.5 \text{ M}

V_2 = 500 \text{ mL}

M_1V_1 = M_2V_2

V_1 = \frac{M_2V_2}{M_1}

V_1 = \frac{0.5 \text{ M} \times 500 \text{ mL}}{2 \text{ M}}

V_1 = 125 \text{ mL}

Answer:

125 \text{ mL}

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