1. Given the slope of the original line m_1 = 3 , find the slope of the perpendicular line m_2 = -\frac{1}{3} .
2. Using the point (−6, −2) and the formula for a line y = mx + b , plug in the point and the new slope:
-2 = -\frac{1}{3}(-6) + b
3. Solve for b :
-2 = 2 + b
b = -4
4. The equation of the line in slope-intercept form is:
y = -\frac{1}{3}x - 4
**Answer:**
y = -\frac{1}{3}x - 4