Solution:
1. Given equation: 2(3x + 1) = 20
2. Distribute the 2 on the left side:
2 \cdot 3x + 2 \cdot 1 = 6x + 2
3. Simplified equation: 6x + 2 = 20
4. Subtract 2 from both sides:
6x = 20 - 2
6x = 18
5. Divide both sides by 6 to solve for x:
x = \frac{18}{6}
x = 3