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4x21 using doubling twice strategy
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4x21 using doubling twice strategy
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Answer to a math question 4x21 using doubling twice strategy
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Answers
1. First doubling:
4 \times 21 = (2 \times 21) \times 2
2. Simplify inside the parentheses:
2 \times 21 = 42
3. Second doubling:
42 \times 2 = 84
Answer:
4 \times 21 = 84
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(3b)⋅(5b^2)⋅(6b^3)
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