1. Use the kinematic equation:
v^2 = u^2 + 2as
2. Substitute the values (\( v = 0 \), \( u = 10 \), \( a = -9.8 \)):
0 = 10^2 + 2(-9.8)s
3. Simplify the equation:
0 = 100 - 19.6s
4. Solve for \( s \):
19.6s = 100
s = \frac{100}{19.6}
s \approx 5.10
Answer: The maximum height of the ball is s \approx 5.10 meters.