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A box contains 7 blue balls and 3 red balls. Two balls were picked at random at a time with replacement, compute the probability that both were of the different color

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Answer to a math question A box contains 7 blue balls and 3 red balls. Two balls were picked at random at a time with replacement, compute the probability that both were of the different color

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Timmothy
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To compute the probability that both balls picked are of different colors, we can calculate the probability of picking a blue ball first and a red ball second, and then add it to the probability of picking a red ball first and a blue ball second.

Step 1: Calculate the probability of picking a blue ball first and a red ball second.
The probability of picking a blue ball first is \frac{7}{10} . Since we replace the ball after the first pick, the probability of picking a red ball second is also \frac{3}{10} .
Therefore, the probability of picking a blue ball first and a red ball second is \frac{7}{10} \cdot \frac{3}{10} .

Step 2: Calculate the probability of picking a red ball first and a blue ball second.
The probability of picking a red ball first is \frac{3}{10} . Since we replace the ball after the first pick, the probability of picking a blue ball second is also \frac{7}{10} .
Therefore, the probability of picking a red ball first and a blue ball second is \frac{3}{10} \cdot \frac{7}{10} .

Step 3: Add the probabilities from Step 1 and Step 2 to get the final answer.
The probability that both balls picked are of different colors is:
\frac{7}{10} \cdot \frac{3}{10} + \frac{3}{10} \cdot \frac{7}{10} = \frac{21}{100} + \frac{21}{100} = \frac{42}{100} = \frac{21}{50}

Answer: The probability that both balls picked are of different colors is \frac{21}{50}

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