Question

Assume that when Human Resource managers are randomly selected, 53% say job applicants should follow up within two weeks. If 6 human resource managers are randomly selected, find the probability that 4 of them say job applicants should follow up within two weeks.

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Murray

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80 Answers

1. Calculate the binomial coefficient \( \binom{6}{4} \):

\binom{6}{4} = \frac{6!}{4!(6-4)!} = \frac{6 \times 5}{2 \times 1} = 15

2. Calculate \( (0.53)^4 \):

(0.53)^4=0.53\times0.53\times0.53\times0.53\approx0.07890481

3. Calculate \( (1-0.53)^{6-4} = (0.47)^2 \):

(0.47)^2 = 0.47 \times 0.47 = 0.2209

4. Put these into the formula:

P(X=4)=15\times0.07890481\times0.2209\approx0.26145

So, the probability that exactly 4 out of 6 HR managers say job applicants should follow up within two weeks is approximately:

0.2615

2. Calculate \( (0.53)^4 \):

3. Calculate \( (1-0.53)^{6-4} = (0.47)^2 \):

4. Put these into the formula:

So, the probability that exactly 4 out of 6 HR managers say job applicants should follow up within two weeks is approximately:

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