Question
Assume that when Human Resource managers are randomly selected, 53% say job applicants should follow up within two weeks. If 6 human resource managers are randomly selected, find the probability that 4 of them say job applicants should follow up within two weeks.
149
likes745 views
Answer to a math question Assume that when Human Resource managers are randomly selected, 53% say job applicants should follow up within two weeks. If 6 human resource managers are randomly selected, find the probability that 4 of them say job applicants should follow up within two weeks.
Murray
4.590 Answers
1. Calculate the binomial coefficient \( \binom{6}{4} \):
\binom{6}{4} = \frac{6!}{4!(6-4)!} = \frac{6 \times 5}{2 \times 1} = 15
2. Calculate \( (0.53)^4 \):
(0.53)^4=0.53\times0.53\times0.53\times0.53\approx0.07890481
3. Calculate \( (1-0.53)^{6-4} = (0.47)^2 \):
(0.47)^2 = 0.47 \times 0.47 = 0.2209
4. Put these into the formula:
P(X=4)=15\times0.07890481\times0.2209\approx0.26145
So, the probability that exactly 4 out of 6 HR managers say job applicants should follow up within two weeks is approximately:
0.2615
2. Calculate \( (0.53)^4 \):
3. Calculate \( (1-0.53)^{6-4} = (0.47)^2 \):
4. Put these into the formula:
So, the probability that exactly 4 out of 6 HR managers say job applicants should follow up within two weeks is approximately:
Frequently asked questions (FAQs)
Math question: "Factor the expression 4xΒ² + 12x + 9 completely using the distributive property.
+
Write a math question for the characteristics of the tangent function f(x) = tan(x): What is the equation of the asymptotes of the tangent function?
+
Math question: What is the smallest positive integer value of n satisfying the equation n^3 + m^3 = d^3 for distinct positive integers m and d, as stated in Fermatβs Theorem?
+
New questions in Mathematics