Benjamin bought tokens at a funfair. He used 3/8 of them at the ring-toss booth and 2/5 of the remaining tokens at the darts booth. He then bought another 35 tokens and had 10 tokens more than what he had at first. How many tokens did Benjamin have at first?

Let's say Benjamin had x tokens at first.

1. Benjamin used \frac{3}{8} of the tokens at the ring-toss booth, which leaves him with x-\frac{3x}{8}=\frac{8x-3x}{8}=\frac{5x}{8} tokens.

2. Benjamin used \frac{2}{5} of the remaining tokens at the darts booth, which leaves him with \frac{5x}{8}-\frac{2}{5}\times\frac{5x}{8}=\frac{5x}{8}-\frac{2x}{8}=\frac{3x}{8} tokens.

3. Benjamin then bought another 35 tokens, so now he has \frac{3x}{8} + 35 tokens.

4. According to the problem, he had 10 tokens more than what he had at first:

\frac{3x}{8} + 35 = x + 10

\frac{3x}{8} = x - 25

3x = 8x - 200

5x = 200

x = 40

Therefore, Benjamin had 40 tokens at first.

Answer:

40