Question
Benjamin bought tokens at a funfair. He used 3/8 of them at the ring-toss booth and 2/5 of the remaining tokens at the darts booth. He then bought another 35 tokens and had 10 tokens more than what he had at first. How many tokens did Benjamin have at first?
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Answer to a math question Benjamin bought tokens at a funfair. He used 3/8 of them at the ring-toss booth and 2/5 of the remaining tokens at the darts booth. He then bought another 35 tokens and had 10 tokens more than what he had at first. How many tokens did Benjamin have at first?
Hester
4.8117 Answers
Let's say Benjamin had x
1. Benjamin used\frac{3}{8} x-\frac{3x}{8}=\frac{8x-3x}{8}=\frac{5x}{8}
2. Benjamin used\frac{2}{5} \frac{5x}{8}-\frac{2}{5}\times\frac{5x}{8}=\frac{5x}{8}-\frac{2x}{8}=\frac{3x}{8}
3. Benjamin then bought another 35 tokens, so now he has\frac{3x}{8} + 35
4. According to the problem, he had 10 tokens more than what he had at first:
\frac{3x}{8} + 35 = x + 10
\frac{3x}{8} = x - 25
3x = 8x - 200
5x = 200
x = 40
Therefore, Benjamin had 40 tokens at first.
Answer:
40
1. Benjamin used
2. Benjamin used
3. Benjamin then bought another 35 tokens, so now he has
4. According to the problem, he had 10 tokens more than what he had at first:
Therefore, Benjamin had 40 tokens at first.
Answer:
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