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By differentiating the function f(x)=(x³−6x)⁷ we will obtain

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Answer to a math question By differentiating the function f(x)=(x³−6x)⁷ we will obtain

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Andrea
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$f '\left( x \right)=\frac{ \mathrm{d} }{ \mathrm{d}x} \left( {\left( {x}^{3}-6x \right)}^{7} \right)$
$f '\left( x \right)=\frac{ \mathrm{d} }{ \mathrm{d}g} \left( {g}^{7} \right) \times \frac{ \mathrm{d} }{ \mathrm{d}x} \left( {x}^{3}-6x \right)$
$f '\left( x \right)=7{g}^{6} \times \frac{ \mathrm{d} }{ \mathrm{d}x} \left( {x}^{3}-6x \right)$
$f '\left( x \right)=7{g}^{6} \times \left( 3{x}^{2}-6 \right)$
$f '\left( x \right)=7{\left( {x}^{3}-6x \right)}^{6} \times \left( 3{x}^{2}-6 \right)$
$f '\left( x \right)=\left( 21{x}^{2}-42 \right) \times {\left( {x}^{3}-6x \right)}^{6}$

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