Consider the following question conditions. There are two ice skaters -Pam and Jakob. In order for them to skate either one of them has to skate in front of the second one. They skate 8 rounds which is equal to the amount of times they have to skate in front of each other. The question: suppose Pam skate s in front of Jacob in the first round, how many ways they can do their normal training?

Let's break down the problem:

- Pam skates in front of Jakob in the first round.
- After that, for the next 7 rounds, they can switch positions in front of each other.

Let's denote P as Pam and J as Jakob. Since Pam skates in front of Jakob in the first round, the possible arrangement for the first round is P-J.

For the next 7 rounds, they can either have Pam in front of Jakob (P-J) or Jakob in front of Pam (J-P). Since they can switch positions freely, there are 2 options for each round.

So, the total number of ways they can do their normal training is 2^7 = 128 ways.

\textbf{Answer: 128 ways}