Given a point (3, -4) and a slope \( m = 3 \), we can use the point-slope form of the equation of a line, which is
y - y_1 = m(x - x_1)
Substituting \( x_1 = 3 \), \( y_1 = -4 \), and \( m = 3 \) into the equation, we get:
y - (-4) = 3(x - 3)
Simplify the equation:
y + 4 = 3x - 9
Subtract 4 from both sides to isolate \( y \):
y = 3x - 13
Therefore, the main equation of the line is:
y = 3x - 13