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Guido has a quarter of Andrés's money and three times as much as David's money. How much money does each have if the sum of all the amounts is $48,000?

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Answer to a math question Guido has a quarter of Andrés's money and three times as much as David's money. How much money does each have if the sum of all the amounts is $48,000?

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Fred

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1. Declare the variable for Andrés's money:

2. Determine Guido's money which is a quarter of Andrés's:

y = \frac{x}{4}

3. Determine David's money, which is a third of Guido's:

z = \frac{y}{3} = \frac{\frac{x}{4}}{3} = \frac{x}{12}

4. Write the equation that sums their total money:

x + \frac{x}{4} + \frac{x}{12} = 48000

5. Get a common denominator for the fractions:

x + \frac{3x}{12} + \frac{x}{12} = 48000

6. Combine the fractions:

x + \frac{4x}{12} = 48000

7. Simplify the expression:

x + \frac{x}{3} = 48000

8. Eliminate the fraction by multiplying by 3:

3x + x = 144000

9. Simplify further:

4x = 144000

10. Solve for

by dividing by 4:

x = 36000

Final amounts:
- Andrés:

x = 36000

- Guido:

y = \frac{36000}{4} = 9000

- David:

z = \frac{9000}{3} = 3000

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Guido has a quarter of Andrés's money and three times as much as David's money. How much money does each have if the sum of all the amounts is $48,000?

Answer to a math question Guido has a quarter of Andrés's money and three times as much as David's money. How much money does each have if the sum of all the amounts is $48,000?

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