Question
If 2p-1 ; p+1 ; p-1 form a geometric sequence and p≠0 . What are the first three terms
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Answer to a math question If 2p-1 ; p+1 ; p-1 form a geometric sequence and p≠0 . What are the first three terms
Santino
4.5110 Answers
Since it's a geometric sequence, than we can know that:
\frac{p+1}{2p-1}=\frac{p-1}{p+1}
\left(p+1\right)\left(p+1\right)=\left(p-1\right)\left(2p-1\right)
p^2+2p+1=2p^2-3p+1
-p^2+5p=0
-p\left(p-5\right)=0
p=0 or p=5
Since p≠0, then p must be 5. So,
2p-1=2.5-1=9
p+1=5+1=6
p-1=5-1=4
The first three terms are 9, 6 and 4.
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