If 2p-1 ; p+1 ; p-1 form a geometric sequence and p≠0 . What are the first three terms

Since it's a geometric sequence, than we can know that: \frac{p+1}{2p-1}=\frac{p-1}{p+1} \left(p+1\right)\left(p+1\right)=\left(p-1\right)\left(2p-1\right) p^2+2p+1=2p^2-3p+1 -p^2+5p=0 -p\left(p-5\right)=0 p=0 or p=5 Since p≠0, then p must be 5. So, 2p-1=2.5-1=9 p+1=5+1=6 p-1=5-1=4 The first three terms are 9, 6 and 4.