Question

In this fulcrum, for the weights to be in balance, what do the distances d1 and d2 have to be if the overall length is 12 feet? d1 (to the nearest hundredth) = 7.20 feet. d2 (to the nearest hundredth) = feet.

151

likes753 views

Madelyn

4.7

40 Answers

For the fulcrum to balance, the product of weight and distance on both sides of the fulcrum must be the same.
Let d1= x. since total distance is 12, we can write d2 = 12 - x
for the fulcrum to balance:
60x = 50(12 - x)
60x = 600 - 50x
110x = 600
x = 5.45
Thus, d1= 5.45
and
d2= 12 - d1 = 12 - 5.45 = 6.55
d1 = 5.45
d2 = 6.55

Frequently asked questions (FAQs)

How many different ways can a committee of 4 members be chosen from a group of 10 candidates?

+

Question: Solve the cubic equation x^3 + 4x^2 - 3x + 2 = 0.

+

Question: Plot the graph of the exponential function y = 3^x, for x ranging from -2 to 2. Indicate the coordinates of the points on the graph.

+

New questions in Mathematics