in this fulcrum for the weights to be in balance what do the distances d1 and d2 have to be if the overall length is 12 fe
Question
In this fulcrum, for the weights to be in balance, what do the distances d1 and d2 have to be if the overall length is 12 feet?
d1 (to the nearest hundredth) =
7.20
feet.
d2 (to the nearest hundredth) =
feet.
151
likes
753 views
Answer to a math question In this fulcrum, for the weights to be in balance, what do the distances d1 and d2 have to be if the overall length is 12 feet?
d1 (to the nearest hundredth) =
7.20
feet.
d2 (to the nearest hundredth) =
feet.
For the fulcrum to balance, the product of weight and distance on both sides of the fulcrum must be the same.
Let d1= x. since total distance is 12, we can write d2 = 12 - x
for the fulcrum to balance:
60x = 50(12 - x)
60x = 600 - 50x
110x = 600
x = 5.45
Thus, d1= 5.45
and
d2= 12 - d1 = 12 - 5.45 = 6.55
d1 = 5.45
d2 = 6.55
Frequently asked questions (FAQs)
What is the length of the perpendicular bisector of a triangle with sides 3, 4, and 5?
+
What is the simplified form of √48?
+
Question: Graph the logarithmic function y = log(x) on the coordinate plane. Determine the x and y-intercepts, asymptotes, and the range of the function. Identify the direction of the graph as it approaches the asymptotes.