 Suppose you have to use a hammer in your hand on a wall with a screw of mass 9300 g. The hammer is 18 cm long. Calculate the torque of the screw?

1. Convert the mass of the screw from grams to kilograms (since 1 kg = 1000 g):
m = \frac{9300 \, \text{g}}{1000} = 9.3 \, \text{kg}

2. Calculate the force due to gravity:
F = m \times g = 9.3 \, \text{kg} \times 9.81 \, \text{m/s}^2 = 91.233 \, \text{N}

3. Convert the length of the hammer from centimeters to meters:
18 \, \text{cm} = 0.18 \, \text{m}

4. Calculate the torque:
\tau = 0.18 \, \text{m} \times 91.233 \, \text{N} = 16.42194 \, \text{Nm}

Thus, the torque about the pivot point due to the weight of the screw at the end of the hammer handle is approximately 16.42 \, \text{Nm} .