Question

The concentrations of bromides in an industrial effluent density 1.00 g/ml are determined using a bromide ion selective electrode. The 0.005 M and 0.010M standards give potential readings of -0.109 v and -0.125 v, respectively. The sample gives a reading of -0.120 v. What is the bromide concentration of the sample in ppm? Br: 79.9 g/mol

292

likes
1461 views

Answer to a math question The concentrations of bromides in an industrial effluent density 1.00 g/ml are determined using a bromide ion selective electrode. The 0.005 M and 0.010M standards give potential readings of -0.109 v and -0.125 v, respectively. The sample gives a reading of -0.120 v. What is the bromide concentration of the sample in ppm? Br: 79.9 g/mol

Expert avatar
Jett
4.7
97 Answers
Los potenciales eléctricos siguen la ecuación de Nernst. Vamos a encontrar la pendiente y la intersección para la línea de calibración primero, y luego usar eso para encontrar la concentración de la muestra.

1. Primeramente, convertimos las concentraciones de Molaridad (M) de las soluciones estándar a su logaritmo en base 10:
\log(0.005) = \log 10^{-2.3} = -2.301
\log(0.010) = \log 10^{-2} = -2

2. Usamos las lecturas de potencial para encontrar la pendiente y la intersección mediante una regresión lineal simple entre el potencial (E) y el logaritmo de la concentración (\(\log [Br^-]\)):
m = \frac{E_2 - E_1}{\log [Br^-]_2 - \log [Br^-]_1} = \frac{-0.125 - (-0.109)}{-2 - (-2.301)}
m = \frac{-0.125 + 0.109}{-2 + 2.301}
m = \frac{-0.016}{0.301}
m \approx -0.05315 \, \text{V}

3. Ahora encontramos la intersección (b) usando una de las parejas de datos:
E = m \log([Br^-]) + b
-0.109 = -0.05315(-2.301) + b
b = -0.109 + 0.1224
b = 0.0134 \, \text{V}

4. Ahora usamos la ecuación de Nernst con la lectura de la muestra para encontrar \(\log[Br^-]\):
E = m \log([Br^-]) + b
-0.120 = -0.05315 \log([Br^-]) + 0.0134
-0.120 - 0.0134 = -0.05315 \log([Br^-])
-0.1334 = -0.05315 \log([Br^-])
\log([Br^-]) = \frac{-0.1334}{-0.05315}
\log([Br^-]) \approx 2.51

5. Deshacemos el logaritmo para encontrar la concentración en M:
[Br^-] = 10^{2.51}
[Br^-] \approx 0.00309 \, \text{M}

6. Convertimos la concentración de M a ppm usando la masa molar de Br:
\text{ppm} = [Br^-] (\text{M}) \times \text{masa molar de Br} \times \frac{\text{densidad de la muestra}}{\text{densidad del agua}} \times 1000
\text{ppm} = 0.00309 \times 79.9 \times 1 \times 1000
\text{ppm} \approx 49.9 \ \text{ppm}

Respuesta: 49.9 \ \text{ppm}

Frequently asked questions (FAQs)
Question: Expand and simplify the expression (5x + 3)(2x - 4) using the distributive property.
+
What is the number of ways to choose 3 out of 8 distinct items?
+
Math question: "If log base 10 of x equals 2 and log base 10 of y equals 3, what is the value of log base 10 of (x^2 * y^3)?"
+
New questions in Mathematics
Let 𝑢 = 𝑓(𝑥, 𝑦) = (𝑒^𝑥)𝑠𝑒𝑛(3𝑦). Check if 9((𝜕^2) u / 𝜕(𝑥^2)) +((𝜕^2) 𝑢 / 𝜕(𝑦^2)) = 0
The time it takes for a person to travel 300 m is 15 minutes. What is their speed in meters per second?
10.Silvana must knit a blanket in 9 days. Knitting 8 hours a day, at the end of the fifth day, only 2/5 of the blanket was done. To be able to finish on time, how many hours will Silvana have to knit per day?
How many percent is one second out a 24 hour?
what is 3% of 105?
1 plus 1
(2x+5)^3+(x-3)(x+3)
4. Show that if n is any integer, then n^2 3n 5 is an odd integer
2x+4x=
find f(x) for f'(x)=3x+7
Two business partners have a bank balance of $17,942.00. After the first year their interest brings their balance to $18,928.91. What rate of interest is earned?
4+168×10³×d1+36×10³×d2=-12 -10+36×10³×d1+72×10³×d2=0
Fill in the P(X-x) values to give a legitimate probability distribution for the discrete random variable X, whose possible values are -5 ,3 , 4, 5 , and 6.
Write an expression using compatible numbers that can be used to estimate the quotient 629\86
Find sup { x∈R, x²+3<4x }. Justify the answer
X^X =49 X=?
a) 6x − 5 > x + 20
Solve the following 9x - 9 - 6x = 5 + 8x - 9
Sodium 38.15 38.78 38.5 38.65 38.79 38.89 38.57 38.59 38.59 38.8 38.63 38.43 38.56 38.46 38.79 38.42 38.74 39.12 38.5 38.42 38.57 38.37 38.71 38.71 38.4 38.56 38.39 38.34 39.04 38.8 A supplier of bottled mineral water claims that his supply of water has an average sodium content of 36.6 mg/L. The boxplot below is of the sodium contents levels taken from a random sample of 30 bottles. With this data investigate the claim using SPSS to apply the appropriate test. Download the data and transfer it into SPSS. Check that your data transfer has been successful by obtaining the Std. Error of the mean for your data which should appear in SPSS output as 0.03900.. If you do not have this exact value, then you may have not transferred your data from the Excel file to SPSS correctly. Do not continue with the test until your value agrees as otherwise you may not have correct answers. Unless otherwise directed you should report all numeric values to the accuracy displayed in the SPSS output that is supplied when your data has been transferred correctly. In the following questions, all statistical tests should be carried out at the 0.05 significance level. Sample mean and median Complete the following concerning the mean and median of the data. mean =  mg/L 95% CI:  to  mg/L Based upon the 95% confidence interval, is it plausible that the average sodium content is 36.9 mg/L?      median:  mg/L The median value is      36.9 mg/L. Skewness Complete the following concerning the skewness of the data. Skewness statistic =        Std. Error =  The absolute value of the skewness statistic     less than 2 x Std. Error Therefore the data can be considered to come from a population that is      . Normality test Complete the following summary concerning the formal testing of the normality of the data. H0: The data come from a population that     normal H1: The data come from a population that     normal Application of the Shapiro-Wilk test indicated that the normality assumption     reasonable for sodium content (S-W(  )=  , p=   ). Main test Using the guidelines you have been taught that consider sample size, skewness and normality, choose and report the appropriate main test from the following ( Appropriate ONE ) You have selected that you wish to report the one-sample t-test. H0: The mean sodium content     equal to 36.9 mg/L H1: The mean sodium content     equal to 36.9 mg/L Application of the one-sample t-test indicated that the mean is      36.9 mg/L (t(  ) =  , p =   ). You have selected that you wish to report the Wilcoxon signed rank test. H0: The median sodium content     equal to 36.9 mg/L H1: The median sodium content     equal to 36.9 mg/L Application of the Wilcoxon signed rank test indicated that the median is      36.9 mg/L (z =  , N =  , p =   ).
How many digits are there in Hindu-Arabic form of numeral 26 × 1011