Question
the mean of a group of monthly incomes with a normal distribution,l for a large set of mid-level technicians in large mining in Chile, is equivalent to $1,000,000, the standard deviation is $100,000. a) What is the value of z for an income of $1,100,000? And for one of $900,000?
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Answer to a math question the mean of a group of monthly incomes with a normal distribution,l for a large set of mid-level technicians in large mining in Chile, is equivalent to $1,000,000, the standard deviation is $100,000. a) What is the value of z for an income of $1,100,000? And for one of $900,000?
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Solution:
First, we need the formula to calculate the z-value:
z = \frac{X - \mu}{\sigma}
Given:
\mu = 1,000,000
\sigma = 100,000
1) For an income of $1,100,000:
X = 1,100,000
z = \frac{1,100,000 - 1,000,000}{100,000} = \frac{100,000}{100,000} = 1
2) For an income of $900,000:
X = 900,000
z = \frac{900,000 - 1,000,000}{100,000} = \frac{-100,000}{100,000} = -1
First, we need the formula to calculate the z-value:
Given:
1) For an income of $1,100,000:
2) For an income of $900,000:
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