Question
the mean of a group of monthly incomes with a normal distribution,l for a large set of mid-level technicians in large mining in Chile, is equivalent to $1,000,000, the standard deviation is $100,000. a) What is the value of z for an income of $1,100,000? And for one of $900,000?
166
likes832 views
Answer to a math question the mean of a group of monthly incomes with a normal distribution,l for a large set of mid-level technicians in large mining in Chile, is equivalent to $1,000,000, the standard deviation is $100,000. a) What is the value of z for an income of $1,100,000? And for one of $900,000?
Bud
4.692 Answers
Solution:
First, we need the formula to calculate the z-value:
z = \frac{X - \mu}{\sigma}
Given:
\mu = 1,000,000
\sigma = 100,000
1) For an income of $1,100,000:
X = 1,100,000
z = \frac{1,100,000 - 1,000,000}{100,000} = \frac{100,000}{100,000} = 1
2) For an income of $900,000:
X = 900,000
z = \frac{900,000 - 1,000,000}{100,000} = \frac{-100,000}{100,000} = -1
First, we need the formula to calculate the z-value:
Given:
1) For an income of $1,100,000:
2) For an income of $900,000:
Frequently asked questions (FAQs)
What is the limit as x approaches 0 of (sin(3x) - 3sin(x))/x?
+
Question: Find the standard deviation of the data set {10, 15, 20, 25, 30}.
+
What is the rule for congruence of triangles involving corresponding sides and angles?
+
New questions in Mathematics