1. Write down the original equation: 3x + 6 = 24 .
2. Subtract 6 from both sides: 3x + 6 - 6 = 24 - 6 leading to 3x = 18 .
3. Divide both sides by 3: x = \frac{18}{3} .
4. Simplify the solution: x = 6 .
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Question: Find the absolute extrema of y = x^2 - 4x + 3 on the interval [-2, 5].