Total resistance of four similar bulbs in parallel is 75 Ohm. What is the resistance of one bulb? (2 points) a. 300 Ohm b. 18.75 Ohm c. 75 Ohm d. 0.013 Ohm Explain your answer:

1. When resistors (or bulbs) are connected in parallel, the total resistance can be found using the formula:
\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4}

2. Since all the bulbs (resistors) are the same, let \( R \) be the resistance of one bulb. Therefore:
\frac{1}{R_{total}} = \frac{1}{R} + \frac{1}{R} + \frac{1}{R} + \frac{1}{R}
or
\frac{1}{75} = \frac{4}{R}

3. Solving for \( R \):
\frac{4}{R} = \frac{1}{75}
R = 4 \times 75
R = 300 \, \Omega

Thus, the resistance of one bulb is 300 \, \Omega .