Question
What critical value should he used to construct a 90% confidence interval for a mean value n=16, s=10.5, and the population appears to be normally distributed? Round to three decimal places
75
likes374 views
Answer to a math question What critical value should he used to construct a 90% confidence interval for a mean value n=16, s=10.5, and the population appears to be normally distributed? Round to three decimal places
Brice
4.8113 Answers
To find the critical value for a 90% confidence interval with n=16, we first need to find the degrees of freedom, which is n-1.
Degrees of freedom (df) = n - 1 = 16 - 1 = 15.
Next, we need to find the critical value from the t-distribution table for a two-tailed test with a confidence level of 90% and 15 degrees of freedom.
Looking up in the t-distribution table, the critical value with a confidence level of 90% and 15 degrees of freedom is approximately 1.753.
Therefore, the critical value to construct a 90% confidence interval for a mean value with n=16 is 1.753.
\boxed{1.753}
Degrees of freedom (df) = n - 1 = 16 - 1 = 15.
Next, we need to find the critical value from the t-distribution table for a two-tailed test with a confidence level of 90% and 15 degrees of freedom.
Looking up in the t-distribution table, the critical value with a confidence level of 90% and 15 degrees of freedom is approximately 1.753.
Therefore, the critical value to construct a 90% confidence interval for a mean value with n=16 is 1.753.
Frequently asked questions (FAQs)
Math question using L'Hospital's Rule: Find the limit as x approaches infinity of (3x^2 + 2x) / (5x^3 + 4x^2 + 1).
+
What is the equation of an exponential function that has a y-intercept at (0, -2) and passes through the point (1, 4)?
+
Math Question: Find the value of f(x) when x = 3, if f(x) is a linear function given by f(x) = x.
+
New questions in Mathematics