Question
What is the probability that we choose a number that is divisible by 3 among the first 20 natural numbers? Justify your answer
216
likes1079 views
Answer to a math question What is the probability that we choose a number that is divisible by 3 among the first 20 natural numbers? Justify your answer
Jett
4.797 Answers
To find the probability of choosing a number that is divisible by 3 among the first 20 natural numbers, we first need to find how many numbers among the first 20 are divisible by 3.
The first multiple of 3 is 3, and the last multiple of 3 that is less than or equal to 20 is 18.
So, the numbers divisible by 3 among the first 20 natural numbers are 3, 6, 9, 12, 15, and 18. There are a total of 6 numbers that are divisible by 3.
Now, the total number of choices is 20 (from 1 to 20).
Therefore, the probability of choosing a number that is divisible by 3 among the first 20 natural numbers is given by:
\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{6}{20} = \frac{3}{10} = 0.3
\boxed{0.3}
The first multiple of 3 is 3, and the last multiple of 3 that is less than or equal to 20 is 18.
So, the numbers divisible by 3 among the first 20 natural numbers are 3, 6, 9, 12, 15, and 18. There are a total of 6 numbers that are divisible by 3.
Now, the total number of choices is 20 (from 1 to 20).
Therefore, the probability of choosing a number that is divisible by 3 among the first 20 natural numbers is given by:
Frequently asked questions (FAQs)
Question: What is the smallest possible value of n in Fermat's theorem equation a^n + b^n = c^n, where a, b, c, and n are positive integers? (
+
Find the derivative of f(x) = 5x^2 + 3x - 2.
+
What is the period of the trigonometric function cos(5x + 3)?
+
New questions in Mathematics