With your 15 meter long vehicle you overtake a vehicle that is just as long. You have a safety distance of 30 meters and want to cut back in 30 meters in front of the vehicle. You are driving at 80 km/h and the vehicle you are overtaking is traveling at 79 km/h. Approximately how long does it take you to overtake?

Name: Solved: With your 15 meter long vehicle you overtake a vehicle that is just as long. You have a safety distance of 30 meters and want to cut back in 30 meters in front of the vehicle. You are driving at 80 km/h and the vehicle you are overtaking is traveling at 79 km/h. Approximately how long does it take you to overtake? - MathMaster
Brand: MathMaster
Rating: 4.9 (255 reviews)

255

likes

1273 views

Answer to a math question With your 15 meter long vehicle you overtake a vehicle that is just as long. You have a safety distance of 30 meters and want to cut back in 30 meters in front of the vehicle. You are driving at 80 km/h and the vehicle you are overtaking is traveling at 79 km/h. Approximately how long does it take you to overtake?

$Expert avatar$

Seamus

4.9

98 Answers

Um die Zeit zu berechnen, die Sie zum Überholen des Fahrzeugs benötigen, müssen wir die Relativgeschwindigkeit zwischen den beiden Fahrzeugen berücksichtigen. Die relative Geschwindigkeit zwischen Ihrem Fahrzeug und dem Fahrzeug, das Sie überholen, ist die Differenz zwischen Ihren Geschwindigkeiten: Relative Geschwindigkeit = Ihre Geschwindigkeit – Geschwindigkeit des überholten Fahrzeugs Relative Geschwindigkeit = (80 km/h) - (79 km/h) = 1 km/h Lassen Sie uns zunächst diese relative Geschwindigkeit in Meter pro Stunde umrechnen, da unsere Entfernungen in Metern angegeben sind: 1 km/h = (1 km/h) * (1000 m/km) = 1000 m/h Die relative Geschwindigkeit beträgt also 1000 Meter pro Stunde. Um herauszufinden, wie lange das Überholen dauert, müssen wir die Distanz berechnen, die Sie zurücklegen müssen, um das Fahrzeug zu überholen: Zurückzulegende Distanz = Länge des überholten Fahrzeugs + Sicherheitsabstand Zurückzulegende Distanz = 15 Meter + 30 Meter = 45 Meter Nun berechnen wir, wie viele Stunden man braucht, um 45 Meter bei einer relativen Geschwindigkeit von 1000 Metern pro Stunde zurückzulegen: Zeit = Distanz / Geschwindigkeit Zeit = 45 Meter / 1000 Meter pro Stunde Zeit = 0,045 Stunden Abschließend konvertieren wir diese Zeit von Stunden in Sekunden (da dies aus praktischen Gründen praktischer ist): 0,045 Stunden * (3600 Sekunden / 1 Stunde) = 162 Sekunden Das Überholen des Fahrzeugs dauert also etwa 162 Sekunden.

Frequently asked questions (FAQs)

Math question: What is the limiting behavior of the constant function f(x) = c as x approaches any real number?

Math question: Find the value of x in log(base 2)(x^2) = log(base 4)(sqrt(x))

What are the values of x in the domain of f(x) = cot x for which f(x) is equal to zero?

New questions in Mathematics

find the value of the tangent if it is known that the cos@= 1 2 and the sine is negative. must perform procedures.

A hotel in the Algarve had to offer 1 week of vacation to one of its employees as an Easter gift in a random choice. It is known that 80 people work in this hotel, 41 of whom are Portuguese and 39 are foreign nationals. There are 14 Portuguese men and 23 foreign women. Using what you know about conditional probability, check the probability that the gift was offered to a Portuguese citizen, knowing that it was a woman.

5) A family with a father, mother and 3 children must sit on five chairs in a row and the only restriction is that the mother must be at one end. In how many different ways can they be seated?

The graph of the equation x²= 4py is a parabola with focus F(_,_) and directrix y=_____ Therefore, the graph of x²=12y is a parabola with focus F(_,_) and a directrix y=_____

Divide 22 by 5 solve it by array and an area model

The equation of the circle that passes through (5,3) and is tangent to the abscissa axis at x=2 is a.(x-2)^2 (y 3)^2 = 9 b.(x-2)^2 (y-3)^2 = 9 c.(x-2)^2 (y-3)^2 = 4 d.(x-2)^2 (y 1)^2 = 4 e.(x-2)^2 (y-1)^2 = 4

-27=-7u 5(u-3)