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write the equation of the line that contains the points 3 7 3 3

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Write the equation of the line that contains the points (3,7) (-3,-3)

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Answer to a math question Write the equation of the line that contains the points (3,7) (-3,-3)

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To write the equation of the line that passes through the points \( (3,7) \) and \( (-3,-3) \), we need to find the slope (m) of the line using the formula: m = \frac{y_2 - y_1}{x_2 - x_1} Substituting the given points into the formula: m = \frac{-3 - 7}{-3 - 3} = \frac{-10}{-6} = \frac{5}{3} Now that we have the slope, we can use the point-slope form of the equation of a line, which is: y - y_1 = m(x - x_1) Using the point \( (3,7) \) and the slope \( \frac{5}{3} \), the equation becomes: y - 7 = \frac{5}{3}(x - 3) To write this in slope-intercept form (\( y = mx + b \)), we distribute the slope and simplify: y - 7 = \frac{5}{3}x - 5 y = \frac{5}{3}x + 2 Therefore, the equation of the line that contains the points \( (3,7) \) and \( (-3,-3) \) is **\( y = \frac{5}{3}x + 2 \)**.

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