-x+2y=0 3x+2y=8 Solve

1. Let's solve the system of equations:

The given equations are:

-x + 2y = 0 \quad ...(1)

3x + 2y = 8 \quad ...(2)

2. First, solve equation (1) for \( x \):

-x + 2y = 0

Rearranging, we have:

x = 2y

3. Substitute \( x = 2y \) into equation (2):

3(2y) + 2y = 8

Simplify:

6y + 2y = 8

8y = 8

y = 1

4. Substitute \( y = 1 \) back into \( x = 2y \):

x = 2(1)

x = 2

5. Therefore, the solution to the system is:

x = 2, \quad y = 1