To evaluate f(-6), we substitute -6 for x in the function f(x) = -1/2x + 5.
Step 1: Plug in x = -6 into the function: f(-6) = -1/2(-6) + 5
Step 2: Simplify the expression: f(-6) = 3 + 5
Step 3: Add the numbers: f(-6) = 8
Answer: f(-6) = 8
Frequently asked questions (FAQs)
What is the equation of a hyperbola with a center at (h, k), vertical transverse axis, and vertices located (h, k + a) and (h, k - a)?
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What are the characteristics of the quadratic function f(x) = x^2? How does the graph of this quadratic function look like? What are the axis of symmetry, vertex coordinates, and y-intercept? How would the graph be affected if the coefficient of x^2 were negative instead of positive?