You have a 1.5 L solution of hydrochloric acid (HCI) with a molarity of 0.80 M.F many moles of HCl are present in the solution?

1. Use the formula for calculating the number of moles: n = C \times V
2. Substitute the given values into the formula:
n = 0.80 \, \text{M} \times 1.5 \, \text{L}
3. Calculate the number of moles:
n = 1.2 \, \text{moles}
4. Therefore, the number of moles of HCl present in the solution is:
1.2 \, \text{moles}