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Solved equation
480=((1)/(3))(6)(h)
fv=po(1+i)^tcalcutet
f(x)=(x-4)^2-5
5*x^2*y^2-23*x*y^2
Theta=arccos ((9)/(15))
(8)/(75)
log _4(x)=3
3.4cos 13
x+62+x+38=180
f(x)=x^2+1,g(x)=2x-2,h(x)=-x-1