Question
1. The motion of a particle is defined by the function 𝑥=12𝑡^3−18𝑡^2+2𝑡+5, where x and t are expressed in meters and seconds respectively. Determine the position and velocity when the acceleration is equal to 0.
123
likes613 views
Answer to a math question 1. The motion of a particle is defined by the function 𝑥=12𝑡^3−18𝑡^2+2𝑡+5, where x and t are expressed in meters and seconds respectively. Determine the position and velocity when the acceleration is equal to 0.
Birdie
4.5103 Answers
Paso 1: Determinar la función que define la velocidad y aceleración de la partícula.
x = 12t^3 - 18t^2 + 2t + 5
dx/dt = velocidad (v) =36t^2 - 36t + 2
d^2(x)/dt^2 = aceleración (a) = 72t - 36
Paso 2: Resuelva para t cuando a=0.
a = 0 = 72t - 36
t = 1/2
Paso 3: Resuelva la velocidad y la posición de la partícula en el tiempo resuelto cuando a=0.
x = 3 metros
v = -7 m/s
Frequently asked questions (FAQs)
What is the value of y when x = 4 in the exponential function y = 3(2)^x?
+
What is the measure of an angle formed by a perpendicular bisector and a side of a triangle?
+
Question: In triangle ABC, angle bisector of angle A divides side BC into segments BD and CD. If BD = 8 cm and CD = 12 cm, what is the length of side BC?
+
New questions in Mathematics