Question
1. The motion of a particle is defined by the function 𝑥=12𝑡^3−18𝑡^2+2𝑡+5, where x and t are expressed in meters and seconds respectively. Determine the position and velocity when the acceleration is equal to 0.
123
likes613 views
Answer to a math question 1. The motion of a particle is defined by the function 𝑥=12𝑡^3−18𝑡^2+2𝑡+5, where x and t are expressed in meters and seconds respectively. Determine the position and velocity when the acceleration is equal to 0.
Birdie
4.5104 Answers
Paso 1: Determinar la función que define la velocidad y aceleración de la partícula.
x = 12t^3 - 18t^2 + 2t + 5
dx/dt = velocidad (v) =36t^2 - 36t + 2
d^2(x)/dt^2 = aceleración (a) = 72t - 36
Paso 2: Resuelva para t cuando a=0.
a = 0 = 72t - 36
t = 1/2
Paso 3: Resuelva la velocidad y la posición de la partícula en el tiempo resuelto cuando a=0.
x = 3 metros
v = -7 m/s
Frequently asked questions (FAQs)
What is the median of a set {3, 7, 2, 9, 5, 4} using the Median Theorem?
+
Math question: Use factoring and distributive property to simplify 3x² + 6xy - 5xz + 9xy - 18yz - 15xz.
+
What is the value of the square root of x minus 5, where x is 36?
+
New questions in Mathematics