Question
1. The motion of a particle is defined by the function 𝑥=12𝑡^3−18𝑡^2+2𝑡+5, where x and t are expressed in meters and seconds respectively. Determine the position and velocity when the acceleration is equal to 0.
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Answer to a math question 1. The motion of a particle is defined by the function 𝑥=12𝑡^3−18𝑡^2+2𝑡+5, where x and t are expressed in meters and seconds respectively. Determine the position and velocity when the acceleration is equal to 0.
Birdie
4.599 Answers
Paso 1: Determinar la función que define la velocidad y aceleración de la partícula.
x = 12t^3 - 18t^2 + 2t + 5
dx/dt = velocidad (v) =36t^2 - 36t + 2
d^2(x)/dt^2 = aceleración (a) = 72t - 36
Paso 2: Resuelva para t cuando a=0.
a = 0 = 72t - 36
t = 1/2
Paso 3: Resuelva la velocidad y la posición de la partícula en el tiempo resuelto cuando a=0.
x = 3 metros
v = -7 m/s
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