(-2,0) and (0,3) Find the equation of the line containing the pair points. Write your solution in slope-intercept form

First, let's find the slope (m) using the formula:

m = \frac{{y_2 - y_1}}{{x_2 - x_1}}

Given points (-2,0) and (0,3), we have:

m = \frac{{3 - 0}}{{0 - (-2)}} = \frac{3}{2}

Next, we can use the point-slope formula to find the equation of the line:

y - y_1 = m(x - x_1)

Using the point (-2,0) and the slope m = 3/2:

y - 0 = \frac{3}{2}(x - (-2))
y = \frac{3}{2}x + 3

Therefore, the equation of the line containing the points (-2,0) and (0,3) in slope-intercept form is:

\boxed{y = \frac{3}{2}x + 3}