A 8-meter simply supported beam is subjected to a uniformly distributed load of 33kN/m. The support are as follows: -Pinned Support at Point A(0-meter position) -Roller Support at Point B(8-meter position)

1. Calculate the total load from the UDL: 33 \, \text{kN/m} \times 8 \, \text{m} = 264 \, \text{kN}
2. Set up the sum of forces equation: R_A + R_B = 264 \, \text{kN}
3. Take moments about A to solve for \( R_B \): 8 \cdot R_B = 264 \cdot 4
4. Solve for \( R_B \): R_B = 132 \, \text{kN}
5. Solve for \( R_A \): R_A = 264 - 132 = 132 \, \text{kN}

Answer: \( R_A = 132 \, \text{kN} \) and \( R_B = 132 \, \text{kN} \)