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a boy is in a swimming pool with index n2 v2 knowing that the smallest index is 2 find the limiting angle of refraction

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a boy is in a swimming pool with index n2=v2. Knowing that the smallest index is 2, find the limiting angle of refraction

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Answer to a math question a boy is in a swimming pool with index n2=v2. Knowing that the smallest index is 2, find the limiting angle of refraction

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Para encontrar o ângulo limite de refração, podemos usar a Lei de Snell, que relaciona os ângulos de incidência e refração aos índices de refração dos dois meios envolvidos: n_1\vezes\sin\theta_1=n_2\vezes\sin\theta_2 Dado que n_2=\sqrt{2} queremos encontrar o ângulo limite de refração à medida que o índice de refração aumenta de \sqrt{2} para um valor mais alto. Neste caso, à medida que o índice de refração aumenta, o ângulo de refração \teta_2 se aproximará de 90 graus. Este ângulo é o ângulo crítico, que é o ângulo limite de refração quando a luz passa de um meio com índice de refração mais alto para outro com índice de refração mais baixo. Além deste ângulo crítico, a luz sofre reflexão interna total. Então, o ângulo limite de refração é \theta_2=90

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