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a student prepares 500 ml of a sodium chloride nacl solution by dissolving 5 0 m vi l na 22 990 grams of naclin water what

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A student prepares 500 mL of a sodium chloride (NaCl) solution by dissolving 5.0 M VI = l Na = 22.990 grams of NaCLin water. What is the molarity of the NaCl solution?

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Answer to a math question A student prepares 500 mL of a sodium chloride (NaCl) solution by dissolving 5.0 M VI = l Na = 22.990 grams of NaCLin water. What is the molarity of the NaCl solution?

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1. Calculate the molar mass of NaCl:

M_{NaCl} = 22.990 + 35.453 = 58.443 \, \text{g/mol}

2. Calculate the number of moles of NaCl:

n = \frac{5.0 \, \text{g}}{58.443 \, \text{g/mol}} = 0.08555 \, \text{mol}

3. Convert volume from mL to L:

V = \frac{500 \, \text{mL}}{1000} = 0.5 \, \text{L}

4. Calculate the molarity:

M = \frac{n}{V} = \frac{0.08555 \, \text{mol}}{0.5 \, \text{L}} = 0.1711 \, \text{M}

Answer: Molarity of the NaCl solution is

0.171\,\text{M}

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