An isosceles triangle with a base of 4 inches and a height of 6 inches is divided vertically in two. Find the area of one of the newly created triangles.

Solution:
1. Given:
- Base of the isosceles triangle: 4 inches
- Height of the triangle: 6 inches
- The triangle is divided vertically into two congruent right triangles.

2. Calculation of one triangle's dimensions:
- When the triangle is divided, each right triangle has a base of \frac{4}{2} = 2 inches (half of the original base).
- The height remains the same for both triangles: 6 inches.

3. Using the formula for the area of a triangle A = \frac{1}{2} \times \text{base} \times \text{height}:
- Area of one of the newly created triangles:
A = \frac{1}{2} \times 2 \times 6 = \frac{1}{2} \times 12 = 6 square inches.