An object of mass 500 g and density 0.8 g/cm³ is immersed in a liquid of density 1.2 g/cm³. What is the volume of the object that remains outside the liquid?



Answer to a math question An object of mass 500 g and density 0.8 g/cm³ is immersed in a liquid of density 1.2 g/cm³. What is the volume of the object that remains outside the liquid?

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Para encontrar el volumen del objeto que queda fuera del líquido, primero debemos determinar el volumen del objeto y luego restar el volumen de la porción que está sumergida en el líquido. Denotemos: - m como la masa del objeto (500 g) - ho_o como densidad del objeto (0,8 g/cm³) - ho_l como densidad del líquido (1,2 g/cm³) - V_o como volumen del objeto (por determinar) - V_s como el volumen de la porción del objeto sumergida en el líquido Sabemos que la densidad ho se define como ho = m/v A partir de esto, podemos reorganizar la ecuación para resolver el volumen: V = m/ho Para el objeto: V_o = m/ho_o Vo = 500/0,8 Vo = 625 cm ^ 3 Ahora, para encontrar el volumen de la porción sumergida en el líquido, podemos utilizar el hecho de que la masa del líquido desplazado es igual a la masa del objeto sumergido: m_desplazamiento = m_ objeto sumergido ho_l *V_s = m Podemos resolver para V_s: V_s = m/ho_l V_s = 500/1,2 V_s=416,67cm^3 Finalmente, para encontrar el volumen del objeto que queda fuera del líquido, restamos el volumen sumergido al volumen total del objeto: Volumen fuera del líquido = V_o - V_s Volumen fuera del líquido = 625 - 416,67 Volumen exterior del líquido = 208,33 cm^3 Entonces, el volumen del objeto que queda fuera del líquido es aproximadamente 208,33 cm^3.

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