Question

Clara usually walks briskly to the farmers' market and it takes her 22 minutes. Today she walked leisurely and it took 61/2 minutes. How much more time than usual did she take to reach the market today?

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Velda

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Subtract the time of travel when Clara walks briskly to the time of travel when she walks leisurely.
\Delta t=\frac{61}{2}-22=\frac{17}{2}\operatorname{mins}
So, Clara took 17/2 more minutes than usual to reach the market today.

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