clara usually walks briskly to the farmers market and it takes her 22 minutes today she walked leisurely and it took 61 2
Question
Clara usually walks briskly to the farmers' market and it takes her 22 minutes. Today she walked leisurely and it took 61/2 minutes. How much more time than usual did she take to reach the market today?
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Answer to a math question Clara usually walks briskly to the farmers' market and it takes her 22 minutes. Today she walked leisurely and it took 61/2 minutes. How much more time than usual did she take to reach the market today?
Subtract the time of travel when Clara walks briskly to the time of travel when she walks leisurely.
\Delta t=\frac{61}{2}-22=\frac{17}{2}\operatorname{mins}
So, Clara took 17/2 more minutes than usual to reach the market today.
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