^x+1 +1 describe transformation","","Solution:\u003Cbr />\n1. Given function:\u003Cbr />\n * \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>y = -24^{x+1} + 1\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Base function:\u003Cbr />\n * \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>y = 4^x\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Identify transformations step-by-step:\u003Cbr />\n - **Translation horizontally**: The function has \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x+1\u003C/math-field>\u003C/math-field> as the exponent instead of \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field>. This indicates a horizontal shift to the left by 1 unit.\u003Cbr />\n - **Vertical stretch and reflection**: The coefficient before \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>4\u003C/math-field>\u003C/math-field> is \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>-2\u003C/math-field>\u003C/math-field>.\u003Cbr />\n - **Vertical stretch**: The factor \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>2\u003C/math-field>\u003C/math-field> indicates that the function is stretched vertically by a factor of \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>2\u003C/math-field>\u003C/math-field>.\u003Cbr />\n - **Reflection**: The negative sign indicates a reflection across the x-axis.\u003Cbr />\n - **Vertical translation**: The \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>+1\u003C/math-field>\u003C/math-field> outside the function indicates a vertical shift upwards by 1 unit.\u003Cbr />\n\u003Cbr />\n4. Describe the complete transformation:\u003Cbr />\n - The function \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>y = 4^x\u003C/math-field>\u003C/math-field> undergoes the following transformations: a horizontal shift to the left by 1 unit, a vertical stretch by a factor of 2, reflection across the x-axis, and finally a vertical shift upwards by 1 unit.",1255,251,"y-2-4-x-1-1-describe-transformation",{"id":44,"category":36,"text_question":45,"photo_question":38,"text_answer":46,"step_text_answer":8,"step_photo_answer":8,"views":47,"likes":48,"slug":49},538086,"Add the polynomials gx=x3-2x2+3x-1+4x2-x+2","Solution: \u003Cbr />\n1. Write down the given polynomials:\u003Cbr />\n- First polynomial: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>gx = x^3 - 2x^2 + 3x - 1\u003C/math-field>\u003C/math-field>\u003Cbr />\n- Second polynomial: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>4x^2 - x + 2\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Align and add the polynomials term by term:\u003Cbr />\n- \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>gx = x^3 - 2x^2 + 3x - 1\u003C/math-field>\u003C/math-field>\u003Cbr />\n- \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>4x^2 - x + 2\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Add the corresponding like terms:\u003Cbr />\n- For \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x^3\u003C/math-field>\u003C/math-field> terms: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x^3\u003C/math-field>\u003C/math-field>\u003Cbr />\n- For \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x^2\u003C/math-field>\u003C/math-field> terms: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>-2x^2 + 4x^2 = 2x^2\u003C/math-field>\u003C/math-field>\u003Cbr />\n- For \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field> terms: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>3x - x = 2x\u003C/math-field>\u003C/math-field>\u003Cbr />\n- For constant terms: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>-1 + 2 = 1\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. The resulting polynomial after addition is:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x^3 + 2x^2 + 2x + 1\u003C/math-field>\u003C/math-field>",739,148,"add-the-polynomials-g-x-x3-2x2-3x-1-4x2-x-2",{"id":51,"category":36,"text_question":52,"photo_question":38,"text_answer":53,"step_text_answer":8,"step_photo_answer":8,"views":54,"likes":55,"slug":56},538085,"R=3m. Calculate the volume of the sphere. Round to the nearest tenth if necessary","1. The formula for the volume of a sphere is \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi R^3 \u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>2. Substitute the given radius \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> R = 3 \\, \\text{m} \u003C/math-field>\u003C/math-field> into the formula:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi 3^3 \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>3. Calculate \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> 3^3 = 27 \u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>4. Thus, the volume becomes:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi \\times 27 \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>5. Simplify the expression:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4 \\times 27}{3} \\pi = 36 \\pi \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>6. Use the approximation \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\pi \\approx 3.1416 \u003C/math-field>\u003C/math-field> :\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V \\approx 36 \\times 3.1416 \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>7. Calculate the approximate volume:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V\\approx113.0973\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>8. Round to the nearest tenth:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V \\approx 113.1 \\, \\text{m}^3 \u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>Therefore, the volume of the sphere is approximately \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> 113.1 \\, \\text{m}^3 \u003C/math-field>\u003C/math-field> .",1203,241,"r-3m-calculate-the-volume-of-the-sphere-round-to-the-nearest-tenth-if-necessary",{"id":58,"category":36,"text_question":59,"photo_question":38,"text_answer":60,"step_text_answer":8,"step_photo_answer":8,"views":61,"likes":62,"slug":63},538084,"Width of 12 in. Calculate the volume of the sphere. Round to the nearest tenth if necessary","1. Identify the radius of the sphere. Given the width is 12 inches, the diameter is 12 inches. Therefore, the radius is half of the diameter:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> r = \\frac{12}{2} = 6 \\, \\text{in} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Use the formula for the volume of a sphere:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi r^3 \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Substitute the radius into the formula:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi 6^3 \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. Calculate:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V = \\frac{4}{3} \\pi \\times 216 = \\frac{864}{3} \\pi = 288 \\pi \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n5. Approximate using \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\pi \\approx 3.1416 \u003C/math-field>\u003C/math-field>:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> V \\approx 288 \\times 3.1416 = 904.8 \\, \\text{in}^3 \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n6. The volume of the sphere, rounded to the nearest tenth, is approximately:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> 904.8 \\, \\text{in}^3 \u003C/math-field>\u003C/math-field>",278,56,"width-of-12-in-calculate-the-volume-of-the-sphere-round-to-the-nearest-tenth-if-necessary",{"id":65,"category":36,"text_question":66,"photo_question":38,"text_answer":67,"step_text_answer":8,"step_photo_answer":8,"views":68,"likes":69,"slug":70},538083,"Calculate the volume tothenearesttenthofacubiccentimeter of a golf ball whose diameter is 4.267cm","1. The formula for the volume of a sphere is given by \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V = \\frac{4}{3} \\pi r^3\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>2. The diameter of the golf ball is given as 4.267 cm, so the radius is half of that: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>r = \\frac{4.267}{2} = 2.1335 \\, \\text{cm}\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>3. Substitute the radius into the volume formula: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V = \\frac{4}{3} \\pi 2.1335^3\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>4. Calculate the cube of the radius: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>2.1335^3 = 9.707432537375\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>5. Substitute this back into the formula: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V=\\frac{4}{3}\\pi\\times9.707432537375\\approx40.7\\,\\text{cm}^3\u003C/math-field>\u003C/math-field> .\u003Cbr>\u003Cbr>6. The volume of the golf ball is approximately \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>40.7\\,\\text{cm}^3\u003C/math-field>\u003C/math-field> .",1440,288,"calculate-the-volume-to-the-nearest-tenth-of-a-cubic-centimeter-of-a-golf-ball-whose-diameter-is-4-267cm",{"id":72,"category":36,"text_question":73,"photo_question":38,"text_answer":74,"step_text_answer":8,"step_photo_answer":8,"views":75,"likes":76,"slug":77},538082,"Find the length of each base edge tothenearesttenthofameter of the 24m tall glass square pyramids of the Muttart Conservatory in Alberta, Canada, if each contains 5280m^3 of space","1. Volume V of a square pyramid is given by the formula:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>V = \\frac{1}{3} B h\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>where B is the area of the base and h is the height of the pyramid.\u003Cbr>\u003Cbr>2. Given that the height h = 24 m and the volume V = 5280 m^3.\u003Cbr>\u003Cbr>3. The base is square, so if the side length of the base is s, then:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>B = s^2\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>4. Substituting into the volume formula:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>5280 = \\frac{1}{3} s^2 \\times 24\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>5. Simplify and solve for s^2:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>5280 = 8 s^2\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>s^2 = \\frac{5280}{8} = 660\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>6. Solve for s:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>s = \\sqrt{660} \\approx 25.7\u003C/math-field>\u003C/math-field> \u003Cbr>\u003Cbr>7. To find the length of each base edge to the nearest tenth of a meter, compute:\u003Cbr>\u003Cbr>\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>s \\approx 25.7 \\, \\text{m}\u003C/math-field>\u003C/math-field>",418,84,"find-the-length-of-each-base-edge-to-the-nearest-tenth-of-a-meter-of-the-24m-tall-glass-square-pyramids-of-the-muttart-conservatory-in-alberta-canada-if-each-contains-5280m-3-of-space",{"id":79,"category":36,"text_question":80,"photo_question":38,"text_answer":81,"step_text_answer":8,"step_photo_answer":8,"views":82,"likes":83,"slug":84},538081,"An observer is 150 meters away\n distance of a hot air balloon online\n straight line at ground level. From your position,\n measures an elevation angle of 40° up to\n the base of the balloon. At what height is\n find the hot air balloon?","Solution:\u003Cbr />\n1. Dado:\u003Cbr />\n- Distancia horizontal desde el observador hasta la base del globo: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>d = 150 \\ m\u003C/math-field>\u003C/math-field>\u003Cbr />\n- Ángulo de elevación: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>\\theta = 40^{\\circ}\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Usamos la función tangente para encontrar la altura \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>h\u003C/math-field>\u003C/math-field> del globo aerostático. La tangente de un ángulo en un triángulo rectángulo es la razón entre la altura y la distancia horizontal:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>\\tantheta = \\frac{h}{d}\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Sustituimos los valores conocidos en la ecuación:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>\\tan40circ = \\frac{h}{150}\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. Resolvemos para \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>h\u003C/math-field>\u003C/math-field>:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>h = 150 \\times \\tan40circ\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n5. Calculamos el valor numérico:\u003Cbr />\n* Usando una calculadora, \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>\\tan40circ \\approx 0.8391\u003C/math-field>\u003C/math-field>\u003Cbr />\n* Entonces: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>h \\approx 150 \\times 0.8391 = 125.865 \\ m\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\nLa altura del globo aerostático es aproximadamente \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>125.865 \\ m\u003C/math-field>\u003C/math-field>.",667,133,"an-observer-is-150-meters-away-distance-of-a-hot-air-balloon-online-straight-line-at-ground-level-from-your-position-measures-an-elevation-angle-of-40-up-to-the-base-of-the-balloon-at-what-hei",{"id":86,"category":36,"text_question":87,"photo_question":38,"text_answer":88,"step_text_answer":8,"step_photo_answer":8,"views":89,"likes":90,"slug":91},538080,"A plane ticket has gone up 18%, now costing 4,720.Howmuchdiditcostbeforetheincrease?","\u003Cmath−fieldread−onlydefault−mode=\"inline−math\"class=\"math−expression\">\u003Cmath−fieldread−only>textSolution:\u003C/math−field>\u003C/math−field>\u003Cbr/>\n1.Definevariables:\u003Cbr/>\n−Let\u003Cmath−fieldread−onlydefault−mode=\"inline−math\"class=\"math−expression\">\u003Cmath−fieldread−only>P\u003C/math−field>\u003C/math−field>betheoriginalpriceoftheplaneticket.\u003Cbr/>\n−\u003Cmath−fieldread−onlydefault−mode=\"inline−math\"class=\"math−expression\">\u003Cmath−fieldread−only>P\u003C/math−field>\u003C/math−field>increasedby18\\frac{x}{15}=\\frac{4}{3}\u003C/math−field>\n\u003Cbr>\n\u003C/div>\n\n\u003Cdiv>\n\n\u003Cmath−fieldstyle=\"font−size:16px;padding:8px;border−radius:8px;border:1pxsolidrgba(0,0,0,.3);box−shadow:000rgba(0,0,0,.2)\n\"read−only>x=20\u003C/math-field>\n \u003Cbr>\n \u003C/div>",467,93,"15-75-of",{"id":149,"category":36,"text_question":150,"photo_question":38,"text_answer":151,"step_text_answer":8,"step_photo_answer":8,"views":152,"likes":90,"slug":153},538067,"Naria Wants to build a perimeter wall fence around 400 sqm lot. The frontage of the lot is 20 meters. The wall height is 1.2 meters below the ground and 3.8 meters above the ground .\nThe cost of constructing the wall is 750 per square meter. Additionally,she plans to install a 5-meter-wide gate that costs ₱50,000.\nHow much Maria spend in total for the wall and the gate\na. Php 281,250.00\nb. Php 106,250.00\nc. Php 331,250.00\nd. Php 218,250.00","1. Determine the dimensions of the lot. Given the frontage is 20 meters, calculate the other side using the area:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Area} = 20 \\times x = 400 \u003C/math-field>\u003C/math-field>\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> x = \\frac{400}{20} = 20 \\, \\text{meters} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. Calculate the perimeter of the lot:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Perimeter} = 2 \\times (20 + 20) = 80 \\, \\text{meters} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Calculate the total height of the wall:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Total height} = 1.2 + 3.8 = 5 \\, \\text{meters} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. Calculate the wall area excluding the gate:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Wall area} = (\\text{Perimeter} - \\text{Gate width}) \\times \\text{Total height} \u003C/math-field>\u003C/math-field>\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Wall area} = (80 - 5) \\times 5 = 75 \\times 5 = 375 \\, \\text{sqm} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n5. Calculate the cost of the wall:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Wall cost} = 375 \\times 750 = 281,250 \\, \\text{PHP} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n6. Calculate total cost including the gate:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Total cost} = \\text{Wall cost} + \\text{Gate cost} \u003C/math-field>\u003C/math-field>\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Total cost} = 281,250 + 50,000 = 331,250 \\, \\text{PHP} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n7. Therefore, the total cost is: \u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Php} \\, 331,250.00 \u003C/math-field>\u003C/math-field>",727,"naria-wants-to-build-a-perimeter-wall-fence-around-400-sqm-lot-the-frontage-of-the-lot-is-20-meters-the-wall-height-is-1-2-meters-below-the-ground-and-3-8-meters-above-the-ground-the-cost-of-const",{"id":155,"category":36,"text_question":156,"photo_question":38,"text_answer":157,"step_text_answer":8,"step_photo_answer":8,"views":158,"likes":76,"slug":159},538066,"2. A rectangular lot has a\n30 meters.\nallocated along the frontage. What is the gross area\nfrontage of 18 meters and a depth of\nHowever, a public right of way of 3 meters is\nReve\nof\nthe\nlot?\na. 520 sqm\nb. 540 sqm\nC. 560 sqm\nd. 580 sqm\nReV","1. Calculate the area of the rectangular lot without the right of way:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> \\text{Area}_{\\text{total}} = \\text{frontage} \\times \\text{depth} = 18 \\, \\text{m} \\times 30 \\, \\text{m} = 540 \\, \\text{sqm} \u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. No need to subtract any area because the problem states that the right of way has already been accounted for in the dimensions provided.\u003Cbr />\n\u003Cbr />\n3. Therefore, the gross area of the lot remains:\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> 540 \\, \\text{sqm} \u003C/math-field>\u003C/math-field> \u003Cbr />\n \u003Cbr />\nThus, the answer is \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>540 \\, \\text{sqm}\u003C/math-field>\u003C/math-field>.",420,"2-a-rectangular-lot-has-a-30-meters-allocated-along-the-frontage-what-is-the-gross-area-frontage-of-18-meters-and-a-depth-of-however-a-public-right-of-way-of-3-meters-is-reve-of-the-lot-a-520-sq",{"id":161,"category":36,"text_question":162,"photo_question":38,"text_answer":163,"step_text_answer":8,"step_photo_answer":8,"views":164,"likes":165,"slug":166},538065,"A triangular lot has a base of 15 meters and heights of 10 meters . What is the total area of the lot ?","1. The formula for the area of a triangle is given by:\u003Cbr />\n\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> A = \\frac{1}{2} \\times \\text{base} \\times \\text{height} \u003C/math-field>\u003C/math-field> \u003Cbr />\n\u003Cbr />\n2. Substitute the given values into the formula:\u003Cbr />\n\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> A = \\frac{1}{2} \\times 15 \\times 10 \u003C/math-field>\u003C/math-field> \u003Cbr />\n\u003Cbr />\n3. Calculate the area:\u003Cbr />\n\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> A = \\frac{1}{2} \\times 150 \u003C/math-field>\u003C/math-field> \u003Cbr />\n\u003Cbr />\n4. Simplify the expression:\u003Cbr />\n\u003Cbr />\n \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> A = 75 \u003C/math-field>\u003C/math-field> \u003Cbr />\n\u003Cbr />\nTherefore, the total area of the lot is \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>75 \\, \\text{square meters}\u003C/math-field>\u003C/math-field>.",425,85,"a-triangular-lot-has-a-base-of-15-meters-and-heights-of-10-meters-what-is-the-total-area-of-the-lot",{"id":168,"category":36,"text_question":169,"photo_question":38,"text_answer":170,"step_text_answer":8,"step_photo_answer":8,"views":171,"likes":172,"slug":173},538064,"4x+(x-3)=2x-(3x-4)+5","Solution:\u003Cbr />\n1. Simplify both sides of the equation.\u003Cbr />\n- Left side: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>4x + (x - 3) = 4x + x - 3 = 5x - 3\u003C/math-field>\u003C/math-field>\u003Cbr />\n- Right side: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>2x - (3x - 4) + 5 = 2x - 3x + 4 + 5 = -x + 9\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n2. The equation is now: \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>5x - 3 = -x + 9\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n3. Add \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field> to both sides to eliminate the \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>-x\u003C/math-field>\u003C/math-field> from the right side and simplify:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>5x + x - 3 = 9\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n4. Simplify: \u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>6x - 3 = 9\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n5. Add 3 to both sides to isolate terms with \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field>:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>6x = 9 + 3\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n6. Simplify:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>6x = 12\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n7. Divide both sides by 6 to solve for \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x\u003C/math-field>\u003C/math-field>:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x = \\frac{12}{6}\u003C/math-field>\u003C/math-field>\u003Cbr />\n\u003Cbr />\n8. Simplify the fraction:\u003Cbr />\n\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x = 2\u003C/math-field>\u003C/math-field>",1332,266,"4x-x-3-2x-3x-4-5",{"first":6,"last":175,"prev":8,"next":10},187,{"current_page":6,"from":6,"last_page":175,"links":177,"path":211,"per_page":212,"to":212,"total":213},[178,181,184,186,188,190,192,195,198,201,204,207,209],{"url":6,"label":179,"active":180},"1",true,{"url":10,"label":182,"active":183},"2",false,{"url":13,"label":185,"active":183},"3",{"url":16,"label":187,"active":183},"4",{"url":19,"label":189,"active":183},"5",{"url":22,"label":191,"active":183},"6",{"url":193,"label":194,"active":183},7,"7",{"url":196,"label":197,"active":183},8,"8",{"url":199,"label":200,"active":183},9,"9",{"url":202,"label":203,"active":183},10,"10",{"url":205,"label":206,"active":183},186,"186",{"url":175,"label":208,"active":183},"187",{"url":10,"label":210,"active":183},"Next »","https://api.math-master.org/api/question",20,3737,{"data":215},{"id":216,"category":36,"slug":217,"text_question":218,"photo_question":8,"text_answer":219,"step_text_answer":8,"step_photo_answer":8,"views":220,"likes":221,"expert":222},535259,"evalu-af1-x-2sin-x-3cos-x-parax-0-4-2","Evalu ́af1(x)=2sin(x)+3cos(x)parax=0,π4,π2","To evaluate \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>f_{1}(x) = 2\\sin(x) + 3\\cos(x)\u003C/math-field>\u003C/math-field> for \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x = 0, \\frac{\\pi}{4}, \\frac{\\pi}{2}\u003C/math-field>\u003C/math-field>, we substitute these values into the function.\u003Cbr />\u003Cbr />1. For \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x = 0\u003C/math-field>\u003C/math-field>,\u003Cbr />\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> f_{1}(0) = 2\\sin(0) + 3\\cos(0) = 2(0) + 3(1) = 3 \u003C/math-field>\u003C/math-field>\u003Cbr />\u003Cbr />2. For \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x = \\frac{\\pi}{4}\u003C/math-field>\u003C/math-field>,\u003Cbr />\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> f_{1}\\left(\\frac{\\pi}{4}\\right) = 2\\sin\\left(\\frac{\\pi}{4}\\right) + 3\\cos\\left(\\frac{\\pi}{4}\\right) = 2\\left(\\frac{\\sqrt{2}}{2}\\right) + 3\\left(\\frac{\\sqrt{2}}{2}\\right) = \\sqrt{2} + \\frac{3\\sqrt{2}}{2} = \\frac{5\\sqrt{2}}{2} \u003C/math-field>\u003C/math-field>\u003Cbr />\u003Cbr />3. For \u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>x = \\frac{\\pi}{2}\u003C/math-field>\u003C/math-field>,\u003Cbr />\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> f_{1}\\left(\\frac{\\pi}{2}\\right) = 2\\sin\\left(\\frac{\\pi}{2}\\right) + 3\\cos\\left(\\frac{\\pi}{2}\\right) = 2(1) + 3(0) = 2 \u003C/math-field>\u003C/math-field>\u003Cbr />\u003Cbr />\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only>\\textbf{Answer:}\u003C/math-field>\u003C/math-field>\u003Cbr />\u003Cmath-field read-only default-mode=\"inline-math\" class=\"math-expression\">\u003Cmath-field read-only> f_{1}(0) = 3, \\quad f_{1}\\left(\\frac{\\pi}{4}\\right) = \\frac{5\\sqrt{2}}{2}, \\quad f_{1}\\left(\\frac{\\pi}{2}\\right) = 2 \u003C/math-field>\u003C/math-field>",1085,217,{"id":223,"name":224,"photo":225,"biography":226,"created_at":8,"updated_at":8,"rating":227,"total_answer":228},21,"Jon","https://api.math-master.org/img/experts/21/21.webp","I passed my matric from Govt.City Muslim school Faisalabad and got first division in school by getting 981/1000 marks.\nAfter matric i got admission in Shiblee Colege Faisalabad and got 883/1100 marks in degree of inter with Math.\nNow currently i'm student of BS Math and running my last semester.",4.6,107,{"data":230},{"questions":231},[232,236,240,244,248,252,256,260,264,268,272,276,280,284,288,292,296,300,304,308],{"id":233,"category":36,"text_question":234,"slug":235},532069,"10.Silvana must knit a blanket in 9 days. Knitting 8 hours a day, at the end of the fifth day, only 2/5 of the blanket was done. To be able to finish on time, how many hours will Silvana have to knit per day?","10-silvana-must-knit-a-blanket-in-9-days-knitting-8-hours-a-day-at-the-end-of-the-fifth-day-only-2-5-of-the-blanket-was-done-to-be-able-to-finish-on-time-how-many-hours-will-silvana-have-to-knit",{"id":237,"category":36,"text_question":238,"slug":239},533923,"The profit G of the company CHUNCHES SA is given by G(x) = 3×(40 – ×), where × is the quantity of items sold. Find the maximum profit.","the-profit-g-of-the-company-chunches-sa-is-given-by-g-x-3-40-where-is-the-quantity-of-items-sold-find-the-maximum-profit",{"id":241,"category":36,"text_question":242,"slug":243},533952,"A brass cube with an edge of 3 cm at 40 °C increased its volume to 27.12 cm3. What is the final temperature that achieves this increase?","a-brass-cube-with-an-edge-of-3-cm-at-40-c-increased-its-volume-to-27-12-cm3-what-is-the-final-temperature-that-achieves-this-increase",{"id":245,"category":36,"text_question":246,"slug":247},533980,"Find the root of x^4-10x^ 5=0 using Newton's method, with a precision of the smallest positive root.","find-the-root-of-x-4-10x-5-0-using-newton-s-method-with-a-precision-of-the-smallest-positive-root",{"id":249,"category":36,"text_question":250,"slug":251},533996,"Suppose 56% of politicians are lawyers if a random sample of size 873 is selected, what is the probability that the proportion of politicians who are lawyers will be less than 55% round your answer to four decimal places","suppose-56-of-politicians-are-lawyers-if-a-random-sample-of-size-873-is-selected-what-is-the-probability-that-the-proportion-of-politicians-who-are-lawyers-will-be-less-than-55-round-your-answer-to",{"id":253,"category":36,"text_question":254,"slug":255},534002,"Equivalent expression of the sequence (3n-4)-(n-2)","equivalent-expression-of-the-sequence-3n-4-n-2",{"id":257,"category":36,"text_question":258,"slug":259},534048,"To celebrate the five-year anniversary of a consultancy specializing in information technology, the administrator decided to draw 3 different qualification courses among its 10 employees. Considering that the same employee cannot be drawn more than once, the total number of different ways of drawing among employees is:","to-celebrate-the-five-year-anniversary-of-a-consultancy-specializing-in-information-technology-the-administrator-decided-to-draw-3-different-qualification-courses-among-its-10-employees-considering",{"id":261,"category":36,"text_question":262,"slug":263},534150,"Primes are numbers divisible only by 1 and themselves; There are infinitely many prime numbers and the first ones are 2, 3, 5, 7, 11, 13, 17, 19, 23, .... Consider a 12-sided die, with the faces numbered from 1 to 12. Out of 4 rolls, the probability that only the first three numbers are primes is:","primes-are-numbers-divisible-only-by-1-and-themselves-there-are-infinitely-many-prime-numbers-and-the-first-ones-are-2-3-5-7-11-13-17-19-23-consider-a-12-sided-die-with-the-faces-numbe",{"id":265,"category":36,"text_question":266,"slug":267},534230,"User\nBefore the election, a poll of 60 voters found the proportion who support the Green candidate to be 25%. Calculate the 90% confidence interval for the population parameter. (Give your answers as a PERCENTAGE rounded to TWO DECIMAL PLACES: exclude any trailing zeros and DO NOT INSERT THE % SIGN)\nGive the lower limit of the 90% confidence interval \nGive the upper limit of the 90% confidence interval","user-before-the-election-a-poll-of-60-voters-found-the-proportion-who-support-the-green-candidate-to-be-25-calculate-the-90-confidence-interval-for-the-population-parameter-give-your-answers-as",{"id":269,"category":36,"text_question":270,"slug":271},534241,"Let A, B, C and D be sets such that | A| = |C| and |B| = |D|. Prove that |A × B| = |C × D|","let-a-b-c-and-d-be-sets-such-that-a-c-and-b-d-prove-that-a-b-c-d",{"id":273,"category":36,"text_question":274,"slug":275},534256,"I. Order to add 40.25+1.31+.45 what is the first action to do ?","i-order-to-add-40-25-1-31-45-what-is-the-first-action-to-do",{"id":277,"category":36,"text_question":278,"slug":279},534282,"There are 3 orchards, a, b and c. Orchard a has 60 fewer trees than orchard b orchard c has 3 times as many trees as orchard b. If the three orchards have 430 trees altogether, how many trees does orchard c have?","there-are-3-orchards-a-b-and-c-orchard-a-has-60-fewer-trees-than-orchard-b-orchard-c-has-3-times-as-many-trees-as-orchard-b-if-the-three-orchards-have-430-trees-altogether-how-many-trees-does-or",{"id":281,"category":36,"text_question":282,"slug":283},534345,"On+January+10+2023+the+CONSTRUCTORA+DEL+ORIENTE+SAC+company+acquires+land+to+develop+a+real estate+project%2C+which+prev%C3% A9+enable+50+lots+for+commercial+use+valued+in+S%2F+50%2C000.00+each+one%2C+the+company+has+as+a+business+model+generate+ cash+flow+through%C3%A9s+of+the+rental%2C+so+47%2C+of+the+50+enabled+lots+are+planned to lease+47%2C+and+ the+rest+will be%C3%A1n+used+by+the+company+for+management%C3%B3n+and+land+control","on-january-10-2023-the-constructora-del-oriente-sac-company-acquires-land-to-develop-a-real-estate-project-2c-which-prev-c3-a9-enable-50-lots-for-commercial-use-valued-in-s-2f-50-2c000-00-each-one-2c",{"id":285,"category":36,"text_question":286,"slug":287},534367,"When Sara was 15 years old, an uncle left her as inheritanceà a sum of 10,000 euros which he invested in a bank that applies the interest rate of 2,5% annual. Today Sara is 18 years and wants to buy a'car, how much she can ò withdraw from the bank?","when-sara-was-15-years-old-an-uncle-left-her-as-inheritancea-a-sum-of-10-000-euros-which-he-invested-in-a-bank-that-applies-the-interest-rate-of-2-5-annual-today-sara-is-18-years-and-wants-to-buy",{"id":289,"category":36,"text_question":290,"slug":291},534371,"Determine a general formula (or formulas) for the solution to the following equation. Then, determine the specific solutions (if any) on the interval [0,2π).\ncos30=0","determine-a-general-formula-or-formulas-for-the-solution-to-the-following-equation-then-determine-the-specific-solutions-if-any-on-the-interval-0-2-cos30-0",{"id":293,"category":36,"text_question":294,"slug":295},534389,"We have received our p&l statement back from accounts. The board has asked for an innovation hub. What items should we prioritise reviewing to decide if we can afford an innovation hub?","we-have-received-our-p-l-statement-back-from-accounts-the-board-has-asked-for-an-innovation-hub-what-items-should-we-prioritise-reviewing-to-decide-if-we-can-afford-an-innovation-hub",{"id":297,"category":36,"text_question":298,"slug":299},534411,"17. A loan for104259 is taken out for 10 years with an annual interest rate of 9.4%, compounded quarterly. What quarterly payment is required to pay the loan off in 10 years? \n\nEnter to the nearest cent twodecimals. Do not use signsorcommasintheanswer.","17−a−loan−for−104259−is−taken−out−for−10−years−with−an−annual−interest−rate−of−9−4−compounded−quarterly−what−quarterly−payment−is−required−to−pay−the−loan−off−in−10−years−enter−to−the−nearest","id":301,"category":36,"textquestion":302,"slug":303,534426,"2X+2=8","2x−2−8","id":305,"category":36,"textquestion":306,"slug":307,534601,"LetIbeanintervalandletf:I→Rbeacontinuousfunctionsuchthatf(I)⊂Q.Show(insymbols)thatfisconstant.","let−i−be−an−interval−and−let−f−i−r−be−a−continuous−function−such−that−f−i−q−show−in−symbols−that−f−is−constant","id":309,"category":36,"textquestion":310,"slug":311,534683,"(3.1x103g2)/(4.56x102g)","3−1x10−3g−2−4−56x10−2g","data":313,"questions":314,[315,319,323,327,331,335,339,343,344,348,352,356,360,364,368,372,376,380,384,388],"id":316,"category":36,"textquestion":317,"slug":318,531999,"Howtofindthevalueofxandywhichsatisfybothequationsx−2y=24and8x−y=117","how−to−find−the−value−of−x−and−y−which−satisfy−both−equations−x−2y−24−and−8x−y−117","id":320,"category":36,"textquestion":321,"slug":322,532000,"Asampleischosenfromapopulationwithy=46,andatreatmentisthenadministeredtothesample.Aftertreatment,the\nsamplemeanisM=47withasamplevarianceofs2=16.Basedonthisinformation,whatisthevalueofCohen′sd?","a−sample−is−chosen−from−a−population−with−y−46−and−a−treatment−is−then−administered−to−the−sample−after−treatment−the−sample−mean−is−m−47−with−a−sample−variance−of−s2−16−based−on−this−inform","id":324,"category":36,"textquestion":325,"slug":326,532040,"8x²−30x−10x²+70x=−30x+10x²−20x²","8x−30x−10x−70x−30x−10x−20x","id":328,"category":36,"textquestion":329,"slug":330,532072,"Sinceoneofthethreeintegerswhoseproductis(−60)is(+4),writethevaluesthattwointegerscantake.","since−one−of−the−three−integers−whose−product−is−60−is−4−write−the−values−that−two−integers−can−take","id":332,"category":36,"textquestion":333,"slug":334,533957,"Determinetheabsoluteextremaofthefunction𝑓(𝑥)=𝑥3−18𝑥296𝑥,ontheinterval[1,10]","determine−the−absolute−extrema−of−the−function−f−x−x3−18x2−96x−on−the−interval−1−10","id":336,"category":36,"textquestion":337,"slug":338,534026,"\"Ifthreewolvescatchthreerabbitsinthreehours,howmanywolveswouldittaketocatchahundredrabbitsinahundredhours?\"\n\nTheansweristhenumberofresponseunits.","if−three−wolves−catch−three−rabbits−in−three−hours−how−many−wolves−would−it−take−to−catch−a−hundred−rabbits−in−a−hundred−hours−the−answer−is−the−number−of−response−units","id":340,"category":36,"textquestion":341,"slug":342,534043,"Theequationofthecirclethatpassesthrough(5,3)andistangenttotheabscissaaxisatx=2is\na.(x−2)2(y3)2=9\nb.(x−2)2(y−3)2=9\nc.(x−2)2(y−3)2=4\nd.(x−2)2(y1)2=4\ne.(x−2)2(y−1)2=4","the−equation−of−the−circle−that−passes−through−5−3−and−is−tangent−to−the−abscissa−axis−at−x−2−is−a−x−2−2−y−3−2−9−b−x−2−2−y−3−2−9−c−x−2−2−y−3−2−4−d−x−2−2−y−1−2−4−e−x−2","id":257,"category":36,"textquestion":258,"slug":259,"id":345,"category":36,"textquestion":346,"slug":347,534118,"Astudyreportsthefollowingfinalnotation:F(3,32)=9.50,p\u003C.05.Howmanytotalparticipantswereinvolvedinthisstudy?\n\n\n\nGroupofanswerchoices\n\n34\n\n32\n\n36","a−study−reports−the−following−final−notation−f−3−32−9−50−p−05−how−many−total−participants−were−involved−in−this−study−group−of−answer−choices−34−32−36","id":349,"category":36,"textquestion":350,"slug":351,534140,"ThecostofunleadedgasolineintheBayAreaoncefollowedanunknowndistributionwithameanof4.59 and a standard deviation of 0.10.SixteengasstationsfromtheBayAreaarerandomlychosen.Weareinterestedintheaveragecostofgasolineforthe16gasstations.\n\n84.Findtheprobabilitythattheaveragepricefor30gasstationsislessthan4.55.\n\ta\t0.6554\n\tb\t0.3446\n\tc\t0.0142\n\td\t0.9858\n\te\t0","the-cost-of-unleaded-gasoline-in-the-bay-area-once-followed-an-unknown-distribution-with-a-mean-of-4-59-and-a-standard-deviation-of-0-10-sixteen-gas-stations-from-the-bay-area-are-randomly-chosen",{"id":353,"category":36,"text_question":354,"slug":355},534172,"Lim x → 0 2x3−10x7 / 5 * x ^ 3 - 4x )=2","lim-x-0-2x-3-10x-7-5-x-3-4x-2",{"id":357,"category":36,"text_question":358,"slug":359},534217,"In the telephone exchange of a certain university, calls come in at a rate of 5 every\n 2 minutes. Assuming a Poisson distribution, the average number of calls per\n second is:\n a) 1/8\n b) 1/12\n c) 1/10\n d) 2/5\n e) 1/24","in-the-telephone-exchange-of-a-certain-university-calls-come-in-at-a-rate-of-5-every-2-minutes-assuming-a-poisson-distribution-the-average-number-of-calls-per-second-is-a-1-8-b-1-12-c-1-10",{"id":361,"category":36,"text_question":362,"slug":363},534280,"A machine produces 255 bolts in 24 minutes. At the same rate, how many bolts would be produced in 40 minutes?","a-machine-produces-255-bolts-in-24-minutes-at-the-same-rate-how-many-bolts-would-be-produced-in-40-minutes",{"id":365,"category":36,"text_question":366,"slug":367},534417,"Let X be a discrete random variable such that EX=3 and VX=5. Let 𝑌 = 2𝑋^2 − 3𝑋. Determine EY.","let-x-be-a-discrete-random-variable-such-that-e-x-3-and-v-x-5-let-y-2x-2-3x-determine-e-y",{"id":369,"category":36,"text_question":370,"slug":371},534421,"Kaya deposits 25,000 into an account that earns 3% interest compounded monthly. How much does Kaya have in the account after 6 years 8 months? Round to the nearest cent.\n\n32,912.50\n30,000\n29,923.71\n30,527.45","kaya-deposits-25-000-into-an-account-that-earns-3-interest-compounded-monthly-how-much-does-kaya-have-in-the-account-after-6-years-8-months-round-to-the-nearest-cent-32-912-50-30-000-29-923-71-30",{"id":373,"category":36,"text_question":374,"slug":375},534446,"To get to a hotel on the hill you have to travel 6 km of uphill road and every kilometer there are 6 sharp curves. Each of the sharp curves is marked by three traffic signs. How many traffic signs are there on the stretch of road that leads to the arbergi?","to-get-to-a-hotel-on-the-hill-you-have-to-travel-6-km-of-uphill-road-and-every-kilometer-there-are-6-sharp-curves-each-of-the-sharp-curves-is-marked-by-three-traffic-signs-how-many-traffic-signs-are",{"id":377,"category":36,"text_question":378,"slug":379},534502,"a) 6x − 5 > x + 20","a-6x-5-x-20",{"id":381,"category":36,"text_question":382,"slug":383},534505,"How do you convert a fraction to a decimal","how-do-you-convert-a-fraction-to-a-decimal",{"id":385,"category":36,"text_question":386,"slug":387},534550,"2+2020202","2-2020202",{"id":389,"category":36,"text_question":390,"slug":391},534658,"A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for\n55.0 min at 100.0 km/h, 14.0 min at 65.0 km/h, and 45.0 min at 60.0 km/h and spends 20.0 min eating lunch and buying gas. a Determine the average speed for the trip.","a-person-travels-by-car-from-one-city-to-another-with-different-constant-speeds-between-pairs-of-cities-she-drives-for-55-0-min-at-100-0-km-h-14-0-min-at-65-0-km-h-and-45-0-min-at-60-0-km-h-and-spe",{"data":393},[394,398,402],{"id":395,"question":396,"answer":397},159784,"What is the result of factoring the mixed number 3 1/2 into a improper fraction?","The mixed number 3 1/2 can be expressed as an improper fraction 7/2.",{"id":399,"question":400,"answer":401},141104,"What are the main characteristics of the tangent function fx = tan x?","The tangent function is periodic with a period of π, undefined at odd multiples of π/2, increases rapidly near odd multiples of π/2, and crosses the x-axis at even multiples of π/2. It has vertical asymptotes at odd multiples of π/2, and its range is all real numbers. The function exhibits reflectional symmetry about both the x-axis and the origin.",{"id":403,"question":404,"answer":405},125256,"Question: \"What is the general equation for graphing an exponential function and how does changing the value of the base affect the shape of the graph?\" ","Answer: The general equation for graphing an exponential function is y = abx, where a represents the initial value or y-intercept, b represents the base, and x represents the input variable. The value of the base b determines the shape and behavior of the graph. If b > 1, the graph is increasing, whereas if 0 \u003C b \u003C 1, it is decreasing. Additionally, the graph gets steeper as the absolute value of b increases.",{"$sicons":407},{"bxl:facebook-circle":408,"bxl:instagram":412,"mdi:web":414,"la:apple":416,"ph:google-logo-bold":419,"ph:google-logo":422},{"left":409,"top":409,"width":410,"height":410,"rotate":409,"vFlip":183,"hFlip":183,"body":411},0,24,"\u003Cpath fill=\"currentColor\" d=\"M12.001 2.002c-5.522 0-9.999 4.477-9.999 9.999c0 4.99 3.656 9.126 8.437 9.879v-6.988h-2.54v-2.891h2.54V9.798c0-2.508 1.493-3.891 3.776-3.891c1.094 0 2.24.195 2.24.195v2.459h-1.264c-1.24 0-1.628.772-1.628 1.563v1.875h2.771l-.443 2.891h-2.328v6.988C18.344 21.129 22 16.992 22 12.001c0-5.522-4.477-9.999-9.999-9.999\"/>",{"left":409,"top":409,"width":410,"height":410,"rotate":409,"vFlip":183,"hFlip":183,"body":413},"\u003Cpath fill=\"currentColor\" d=\"M11.999 7.377a4.623 4.623 0 1 0 0 9.248a4.623 4.623 0 0 0 0-9.248m0 7.627a3.004 3.004 0 1 1 0-6.008a3.004 3.004 0 0 1 0 6.008\"/>\u003Ccircle cx=\"16.806\" cy=\"7.207\" r=\"1.078\" 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